我正在制作一个移动游戏Ballz的克隆版,在这个游戏中你需要在多次击中之后击打一大堆球.就像BrickBreaker类固醇一样.我大部分都在工作,但我无法弄清楚如何一个接一个地射球.我从测试中知道,在拍摄时,球在不同的地方,但在此之后它们会占据相同的空间.
哦顺便说一句,我将它们分开的方式是让球再次回到屏幕之外.所以你可以想象它就像把它们全部放在一个接一个,在屏幕外,在播放器底部之下.
这是我的代码:
import pygame
import math
import random
from vector import *
backgroundColor = (0, 0, 0)
ballColor = (255, 255, 255)
sizeOfOneBlock = 50.0
realDimension = 600.0
blockNumberInLine = int(realDimension/sizeOfOneBlock)
size = [int(realDimension), int(realDimension)]
# eg. probability(1/3)
def probability(chance):
return random.random() <= chance
def abs(x):
if x>=0:
return x
else:
return -x
# the classes used:
# Block, BlockHandler, Ball, Player
class Block():
def __init__(self, strength, i, j):
self.strength = strength
# i and j are numbers between …Run Code Online (Sandbox Code Playgroud) 我正在使用自定义用户模型,使用AbstractUser进行扩展.这是我的models.py:
# -*- coding: utf-8 -*-
from __future__ import unicode_literals
from django.db import models
from django.contrib.auth.models import AbstractUser
from django.contrib.auth.forms import UserCreationForm
from django import forms
# Create your models here.
class User(AbstractUser):
pass
class SignUpForm(UserCreationForm):
first_name = forms.CharField(max_length=30, required=False, help_text='Optional.')
last_name = forms.CharField(max_length=30, required=False, help_text='Optional.')
email = forms.EmailField(max_length=254, help_text='Required. Inform a valid email address.')
class Meta:
model = User
fields = ('username', 'first_name', 'last_name', 'email', 'password1', 'password2', )
enter code here
Run Code Online (Sandbox Code Playgroud)
因此,当我尝试运行开发服务器或迁移数据库时,它会返回以下错误:
Traceback (most recent call last):
File "./manage.py", …Run Code Online (Sandbox Code Playgroud) 我的代码看起来像这样:
var dict = ["a": 1, "b": 2]
var valueInDict = 1
Run Code Online (Sandbox Code Playgroud)
我的问题是,是否可以仅使用值来访问密钥,在本例中为"a".