小编Jac*_*ong的帖子

我一直在尝试搜索如何在python中传递对象引用并键入类似于Java的类型,但没有用.我duno如果这个话题存在于某处.

我的麻烦是我必须将对象引用传递给类构造函数.但我duno如何对一个对象的引用进行类型转换.在java虽然我已经完成了这个,但我必须将代码传输到服务器端.

非常感谢,杰克

class SearchRectangle:
    def __init__(self, lower_left_subgrid_x, lower_left_subgrid_y, rectangle_width, rectangle_height):

        self.min_subgrid_x = int(lower_left_subgrid_x)
        self.max_subgrid_x = int(self.min_subgrid_x + rectangle_width -1)
        self.min_subgrid_y = int(lower_left_subgrid_y)
        self.max_subgrid_y = int(self.min_subgrid_y + rectangle_height -1)

     ...blah



class SearchRectangleMultiGrid:
 # parent rectangle should be a SearchRectangle instance 
    def __init__(self, parent_rectangle):
        self.parent_rectangle = SearchRectangle()parent_rectangle



    # test codes
    test_rect = SearchRectangle(test_subgrid.subgrid_x, test_subgrid.subgrid_y, 18, 18)
    print "\n\nTest SearchRectangle";
    print test_rect.to_string()
    print test_rect.sql_clause

    test_rec_multi = SearchRectangleMultiGrid(test_rect)
    print "\n\nTest SearchRectangleMulti"
    test_rec_multi.parent_rectangle.to_string()