小编JRo*_*ero的帖子

我有以下JSON:

{
  "registration": {
    "name": "Vik Kumar",
    "first_name": "Vik",
    "last_name": "Kumar",
    "bloodGroup": "B-",
    "gender": "male",
    "birthday": "10\/31\/1983",
    "email": "vik.ceo\u0040gmail.com",
    "cellPhone": "1234123456",
    "homePhone": "1234123457",
    "officePhone": "1234123458",
    "primaryAddress": "jdfjfgj",
    "area": "jfdjdfj",
    "location": {
      "name": "Redwood Shores, California",
      "id": 103107903062719
    },
    "subscribe": true,
    "eyePledge": false,
    "reference": "fgfgfgfg"
  }
}

我使用以下代码来解析它:

JsonNode json = new ObjectMapper().readTree(jsonString);
JsonNode registration_fields = json.get("registration");

Iterator<String> fieldNames = registration_fields.getFieldNames();
while(fieldNames.hasNext()){
    String fieldName = fieldNames.next();
    String fieldValue = registration_fields.get(fieldName).asText();
    System.out.println(fieldName+" : "+fieldValue);
}

这工作正常,它打印除了位置的所有值,这是另一层嵌套.我尝试了与上面的代码相同的技巧来传递json.get("location"),但这不起作用.请建议如何使其适用于位置.

基于如何使用xpointer与Xinclude引用元素 ...

当命名空间urn包含多个冒号时,我遇到了包括使用xpointer的嵌套元素的问题.

Test1.xml

<?xml version="1.0" encoding="UTF-8"?>

<Root xmlns="urn:some:namespace">
  <element1 id="001">
    <element2 id="001.1" order="1">
      <element3 id="001.1.1"/>
    </element2>
    <element2 id="001.2" order="2">
      <lement3 id="001.1.2"/>
    </element2>
  </element1>
</Root>

Test2.xml

<?xml version="1.0" encoding="UTF-8"?>

<Root>
  <element1 id="999">
    <element2 id="999.1" order="1">
      <element3 id="999.1.1"/>
    </element2>
  </element1>
</Root>

的merge.xml

<?xml version="1.0"?>

<Root xmlns:xi="http://www.w3.org/2003/XInclude">

  <xi:include href="Test1.xml" xpointer="xmlns(ns=urn:some:namespace)xpointer(/ns:Root/ns:element1)" parse="xml" />
  <xi:include href="Test2.xml" xpointer="xpointer(//Root/element1)" parse="xml" />

</Root>

命令:

xmllint --pretty 1 --xinclude Merge.xml

错误

Merge.xml:5: element include: XInclude error : XPointer evaluation failed: #xmlns(ns=urn:some:namespace)xpointer(/ns:Root/ns:element1)
Merge.xml:5: element include: XInclude error : …

我正在编写一个gradle插件,希望从应用此插件的项目的资源中读取特定的属性文件.要读取这些资源,我需要一个项目的类路径.目前我要去:

org.gradle.api.Project.getBuildscript().getClassLoader().getResourcesAsStream(...)

但即使该项目中存在此类资源,它也始终返回null.

这是我的general.xml档案

<menu xmlns:android="http://schemas.android.com/apk/res/android" >

    <item
        android:id="@+id/action_settings"
        android:orderInCategory="100"
        android:showAsAction="never"
        android:title="@string/action_settings"/>
    <item 
        android:id="@+id/next" 
        android:title="Next" 
        android:visible="true" 
        android:enabled="true" 
        android:showAsAction="always" 
        android:orderInCategory="1">

    </item>
    <item 
        android:id="@+id/Previous"
        android:title="Previous" 
        android:visible="true" 
        android:enabled="true" 
        android:orderInCategory="2" 
        android:showAsAction="always">

    </item>
    <item android:id="@+id/star" 
        android:icon="@drawable/ic_action_important" 
        android:enabled="true" 
        android:orderInCategory="0" 
        android:showAsAction="always" 
        android:title="Star" 
        android:visible="true">
    </item>

</menu>

这是我的代码

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // TODO Auto-generated method stub
    MenuInflater inflater = getMenuInflater();
    inflater.inflate(R.menu.general, menu);
    getSupportActionBar().setDisplayShowHomeEnabled(false);
    getSupportActionBar().setDisplayShowTitleEnabled(false);
    getSupportActionBar().setBackgroundDrawable(new ColorDrawable(Color.parseColor("#003f84")));
    return true;
}

现在,我的问题是菜单项没有显示在操作栏中.我在这里做错了吗？