小编Sat*_*esh的帖子

我正在跑步Xcode 10和iOS 12.1我的iPhone 6S Plus.该应用程序在模拟器中运行时工作,但在Xcode连接我的手机运行我的应用程序时,我收到此错误:

iPhone拒绝了发布请求.

我的iPhone是我的Mac上值得信赖的设备,我有签名证书.我花了几个小时用谷歌搜索解决方案,但没有一个能为我工作.

有人有主意吗？

我是新来的Xcode，我不知道如何设置webview在safe areaiPhone X.我通过各种情侣答案已经走了，但他们并没有帮助。我对这个应用程序的唯一了解是，视图是以编程方式设置的。下面是我的ViewController.swift文件。

import UIKit
import WebKit
import AVFoundation

class ViewController: UIViewController, WKScriptMessageHandler, WKNavigationDelegate, WKUIDelegate
{
    var webView       = WKWebView()
    var containerView = WKWebView() //Footer  Webview

    override func loadView()
    {
        super.loadView()
    }

    override func viewDidLoad()
    {
        super.viewDidLoad()

        let theConfiguration = WKWebViewConfiguration()

        //Bind Swift and Javascript interface through MessageHandler IOSJSObject
        theConfiguration.userContentController.add(self, name: "IOSJSObject")

        /* Webview intialization Start */
        webView = WKWebView(frame: CGRect(x: 0, y: 20, width: UIScreen.main.bounds.width, height: UIScreen.main.bounds.height-65), configuration: theConfiguration)

        containerView = …

我正在尝试使用解析响应JSONDecoder。如果相应的键有值，那么它将很好，但是如果键的值为空，则它将无法编译，并出现以下错误。

valueNotFound（Swift.String，Swift.DecodingError.Context（codingPath：[CodingKeys（stringValue：“ Results”，intValue：nil），_JSONKey（stringValue：“ Index 0”，intValue：0），CodingKeys（stringValue：“ VehicleName”， intValue：nil）]，debugDescription：“期望的字符串值，但发现为null。”，底层错误：nil））

guard let obj = try? JSONDecoder().decode(ShipmentsResponse.self, from: json) else {return}

这是我违抗的货运类

class ShipmentResponse : Codable {

    var ItemId: String = ""
    var VehicleName: String  = ""
    var VehicleNumber: String  = ""

    convenience required init(from decoder: Decoder) throws
    {
        self.init()
        let values = try decoder.container(keyedBy: CodingKeys.self)
        ItemId = try values.decode(String.self, forKey: .ItemId)

        do {
            _ = try values.decode(String.self, forKey: .VehicleName)
        } catch {
            print(error)
        }

        VehicleName = try values.decode(String.self, forKey: .VehicleName)
        VehicleNumber …

我的非常简单的应用程序遇到了麻烦。

我的应用程序只有两个主要内容，UIViewControllers称为新闻和类别，每个都有自己的UINavigationController.

所以在AppDelegate.swift，我这样做了

window = UIWindow(frame: UIScreen.main.bounds)
let tabBarController = UITabBarController()

let newsVC = NewsVC()

// CREATE TAB BAR ITEM WITH TITLE ONLY
let newsVCTabBarItem = UITabBarItem(title: "News", image: nil, tag: 1)
newsVC.tabBarItem = newsVCTabBarItem

let categoryVC = CategoryVC()

// CREATE TAB BAR ITEM WITH TITLE ONLY
let categoryVCTabBarItem = UITabBarItem(title: "Category", image: nil, tag: 2)
categoryVC.tabBarItem = categoryVCTabBarItem

let rootViewControllers = [newsVC, categoryVC]

// CREATE NAVIGATION CONTROLLER FOR EACH OF THEM
tabBarController.viewControllers = …

FlatList当状态messages改变时，我试图滚动到我的末尾。目前我this.refs.flatList.scrollToEnd();在等待一段时间后正在使用，它工作正常。我想要做的是向messages状态添加一个事件侦听器，这样当列表以任何方式更改时，它都会滚动到列表的末尾。我试过

componentDidMount(){
        this.state.messages.addEventListener('change', this._handleNewMessage);
}

但它不起作用。有谁知道我可以实现这一目标的方法？

在内部调用函数时出错navigationOptions。

static navigationOptions = {
    tabBarIcon: ({ tintColor })=> (
      <Icon name='ios-add-circle' style={{ color: tintColor}} />
    ),
    tabBarOnPress: () => {
      this.callingFun();
    },
  }

  callingFun = ()=> {
    console.log('tabBarOnPress:');
  }

错误：

我在操场上玩 RxSwift 时遇到了警告。这是完整的警告消息：

Synchronization anomaly was detected.
- Debugging: To debug this issue you can set a breakpoint in RxSwift/RxSwift/Rx.swift:113 and observe the call stack.
Problem: This behavior is breaking the observable sequence grammar. `next (error | completed)?`
- This behavior breaks the grammar because there is overlapping between sequence events.
Observable sequence is trying to send an event before sending of previous event has finished.
- Interpretation: Two different unsynchronized threads are trying to send some event simultaneously.
This …