小编run*_*i74的帖子

我有一个xml文档,如下所示:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Position>
    <Search>
        <Location>
            <Region>OH</Region>
            <Country>us</Country>
            <Longitude>-816071</Longitude>
            <Latitude>415051</Latitude>
        </Location>
    </Search>
</Position>

我将其读入数据帧:

df = sqlContext.read.format('com.databricks.spark.xml').options(rowTag='Position').load('1.xml')

我可以看到1列:

df.columns
['Search']

print df.select("Search")
DataFrame[Search: struct<Location:struct<Country:string,Latitude:bigint,Longitude:bigint,Region:string>>]

如何访问嵌套列.前位置.区域？

我有2个dataFrames并希望比较它们并返回第一个(df1)中不在第二个(df2)中的行.我找到了一种方法来比较它们并返回差异,但无法弄清楚如何从df1只返回丢失的那些.

import pandas as pd
from pandas import Series, DataFrame

df1 = pd.DataFrame( { 
"City" : ["Chicago", "San Franciso", "Boston"] , 
"State" : ["Illinois", "California", "Massachusett"] } )

df2 = pd.DataFrame( { 
"City" : ["Chicago",  "Mmmmiami", "Dallas" , "Omaha"] , 
"State" : ["Illinois", "Florida", "Texas", "Nebraska"] } )



df = pd.concat([df1, df2])
df = df.reset_index(drop=True)

df_gpby = df.groupby(list(df.columns))
idx = [x[0] for x in df_gpby.groups.values() if len(x) == 1]
blah = df.reindex(idx)