小编Ahm*_*tar的帖子

我正在使用我的XML-RPC服务使用Apache XML-RPC库但是在响应XML-RPC时有垃圾字符,因此库无法解析结果

这是我的XML-RPC程序:

import java.net.URL;

import org.apache.xmlrpc.client.XmlRpcClient;
import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;


public class XMLRpcExample {

    public static void main(String[] args) throws Exception{
        // TODO Auto-generated method stub

        XmlRpcClientConfigImpl cf = new XmlRpcClientConfigImpl();
        cf.setServerURL(new URL("/xmlrpc/object"));
        cf.setBasicUserName("admin");
        cf.setBasicPassword("m_demo");
        cf.setConnectionTimeout(60000);
        XmlRpcClient client = new XmlRpcClient();
        client.setConfig(cf);
        Object[] params = new Object[] {"dbname",1,"m_demo","res.partner","partner_sync_openerp","kapil5drd@bxiz","22"};
        String s =(String)client.execute("execute", params);
        System.out.println(s);
    }

}

但我收到此错误的响应,看起来像这样:

[Fatal Error] :16:16: An invalid XML character (Unicode: 0xc) was found in the element content of the document.
Exception in thread "main" org.apache.xmlrpc.client.XmlRpcClientException: Failed to …

我们可以在neo4j图数据库中拥有一个节点的多个属性来唯一地识别它吗？

类似于RDBMS中的复合主键,用于唯一标识表的一行.

我是c ++的新手,目前在使用时遇到错误strcmp.

我已经定义了如下结构:

struct student
{
 string name;
 int roll;
 float marks;
 dob dobi;
 string dobp;
};
student *p;

然后,我将指针传递给函数以对其进行排序,如下所示:

void sortData(student *p)
{
 int a=0,b=0;
 for (a=0; a<=arraySize; a++)
 {
    for (b=a; b<=arraySize; b++)
    {
        if( strcmp(p[a].name, p[b].name) > 0 ) //Error
        {
           //sort logic yet to be implemented 
        }
    }
 }
}

有人可以指出错误.

错误信息:

呼叫没有匹配功能 strcmp

因此,对于作业,我必须完成一个用于大写字符串的代码.

我试过的是这个:

#include <stdio.h>

void capitalize(char *str)
{
    int i = 0;
    if (str[i] >= 97 && str[i] <= 122)
    {
        str[i] = str[i] - 32;
    }
    else
    {
        i++;
    }
}

void strCopy(char *str2, char *str1)
{
    while (*str2)
    {
      *str1 = *str2;
      str2++;
      str1++;
    }
    *str1 = '\0';
}

int main(int argc, char **argv)
{
    char string1[100] = "This is a really long string!";
    char string2[100];
    strCopy(string1,string2);
    capitalize(string2);
    printf("The original string is \"%s\"\n", string1);
    printf("The capitalized string is …

任何人都可以解释以下行的输出:

sprintf(tempStr,"%s%2s%s",year_str,month_str,day_str);    
count=sscanf(tempStr,"%ld%s",&tempout,other);

它使用日,月和年值创建数字日期.

但是,它如何将数值转换为长整数？

对于例如:你能告诉我,如果年,月和日是2016,02和08,那么这将是输出值tempout.

这里是输入的方式:

    char date_str[20];

    char day_str[2];
    char month_str[2];
    char year_str[2];

    time_t now;
    struct tm* current_time;

    /* get current time */
    now = time(0); 

    /* convert time to tm structure */
    current_time = localtime(&now);

    /* format day string */
    sprintf(day_str,"%02d",current_time->tm_mday);

    /* format month string */
    sprintf(month_str,"%02d",current_time->tm_mon + 1);

    /* format year string */
    sprintf(year_str,"%d",current_time->tm_year);

    /* assemble date string …

对某些人来说这可能是非常基本的,但我似乎无法绕过它.我的任务指示是:

只应改变一个地方.而不是打印

1, 2, 3, 4, 5, 6, 7, 8, 9, 10

Run Code Online (Sandbox Code Playgroud)

打印:

99, 80, 63, 48, 35, 24, 15, 8, 3, 0

Run Code Online (Sandbox Code Playgroud)

码:

public class Lab9
{
    public static void main(String args[])
    {
        int counter;
        counter=1; // do not change this line
        while(counter<=10) // do not change this line
        {
            System.out.println(counter); // do change this line
            counter=counter+1; // do not change this line
        }
        System.exit(0);
    }
}