我的数组中有以下日期(日期并不总是这些日期)
[0] 2012-10-18
[1] 2012-10-19
[2] 2012-10-20
[3] 2012-10-23
[4] 2012-10-24
[5] 2012-10-29
[6] 2012-10-30
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我想将连续的日期分组在一起,所以输出是:
2012-10-18 to 2012-10-20
2012-10-23 to 2012-10-24
2012-10-29 to 2012-10-30
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我将如何在 PHP 中执行此操作?
谢谢!
它需要很长时间才能完成,但希望能够快速获取它收集的信息.
SELECT *
FROM releases
WHERE (artist IN (SELECT artist FROM artist_love WHERE user='Quickinho')
OR
label IN (SELECT label FROM label_love WHERE user='Quickinho')
OR
id IN (SELECT release_id FROM charts_extended WHERE artist IN (SELECT dj FROM dj_love WHERE user='Quickinho'))
OR
id IN (SELECT artist FROM releases WHERE id IN (SELECT release_id FROM charts_extended WHERE user='Quickinho'))
OR
id IN (SELECT label FROM releases WHERE id IN (SELECT release_id FROM charts_extended WHERE user='Quickinho')))
AND
id NOT IN (SELECT release_id FROM charts_extended WHERE …Run Code Online (Sandbox Code Playgroud) 无论如何使用preg_match或strpos识别字符串中是否存在双字节字符?
我收到的中文文本混合英文的XML文件,想跳过包含中文文本的任何文件.XML是utf-8编码的.
使用说明http://docs.python-guide.org/en/latest/starting/install/osx/在OSX 10.10上安装Python/Pip
仅安装才能访问Pip
使用安装的请求 pip install requests
然后脚本
import requests
feed_url = 'http://www.mylocation.com/the_data'
#grab xml from URL
r = requests.get(feed_url)
r.text
print r
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错误是
Traceback (most recent call last):
File "get_all_listings.py", line 1, in <module>
import requests
File "/usr/local/lib/python2.7/site-packages/requests/__init__.py", line 58, in <module>
from . import utils
File "/usr/local/lib/python2.7/site-packages/requests/utils.py", line 12, in <module>
import cgi
File "/usr/local/Cellar/python/2.7.10_2/Frameworks/Python.framework/Versions/2.7/lib/python2.7/cgi.py", line 50, in <module>
import mimetools
File "/usr/local/Cellar/python/2.7.10_2/Frameworks/Python.framework/Versions/2.7/lib/python2.7/mimetools.py", line 6, in <module>
import tempfile
File "/usr/local/Cellar/python/2.7.10_2/Frameworks/Python.framework/Versions/2.7/lib/python2.7/tempfile.py", line 32, in <module>
import …Run Code Online (Sandbox Code Playgroud) 我有以下价值观:
.03
.04
1.23
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我想将0添加到小数位前没有值的任何值.所以输出将是:
0.03
0.04
1.23
Run Code Online (Sandbox Code Playgroud) 我想确定PHP数组中缺少的日期
例如
这个范围
2013-06-12
2013-06-13
2013-06-26
2013-06-27
2013-06-29
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缺少以下日期:
2013-06-14
2013-06-15
2013-06-16
...
2013-06-24
2013-06-25
2013-06-28
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如何识别丢失的日期?
我的视图没有收到我从登录表单发送的任何POST数据.
要测试提交,我想将电子邮件字段输出到浏览器.
从视图返回的输出是 None
的login.html
<form action="/login_email/" method="POST">
{% csrf_token %}
<div class="form-group">
<label for="email">Email address</label>
<input type="email" class="form-control" id="email" placeholder="Email">
</div>
<div class="form-group">
<label for="email">Password</label>
<input type="password" class="form-control" id="password" placeholder="Password">
</div>
<button type="submit" class="btn btn-info">Submit</button>
</form>
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views.py
def login_email(request):
if request.method == 'POST':
email = request.POST.get('email')
password = request.POST.get('password')
return HttpResponse(email)
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