绘制/ information.xml
<vector xmlns:android="http://schemas.android.com/apk/res/android"
android:width="24dp"
android:height="24dp"
android:viewportWidth="24.0"
android:viewportHeight="24.0">
<path
android:fillColor="#FF000000"
android:pathData="M13,9H11V7H13M13,17H11V11H13M12,2A10,10 0,0 0,2 12A10,10 0,0 0,12 22A10,10 0,0 0,22 12A10,10 0,0 0,12 2Z"/>
</vector>
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LayoutofCardView.xml
<ImageView
android:layout_width="24dp"
android:background="#f00"
android:layout_height="24dp"
android:id="@+id/informationImageView"
app:srcCompat="@drawable/information"
tools:src="@drawable/information"
/>
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的build.gradle
apply plugin: 'com.android.application'
android {
compileSdkVersion 23
buildToolsVersion "23.0.2"
defaultConfig {
applicationId "com.company"
minSdkVersion 15
targetSdkVersion 23
versionCode 1
versionName "1.0"
generatedDensities = []
}
aaptOptions {
additionalParameters "--no-version-vectors"
}
buildTypes {
release {
minifyEnabled false
proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
}
}
packagingOptions {
exclude 'META-INF/NOTICE.txt'
exclude …Run Code Online (Sandbox Code Playgroud) public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState)
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如果我们打电话说
fragment.getContext()并且container.getContext将我们得到相同的结果,则主机活动?
也view.getContext()总是返回Activity context或者它可以返回其他类型的context?
android android-context android-fragments android-view android-activity
我正进入(状态,
Caused by java.lang.InternalError: java.util.MissingResourceException: Can't find bundle for base name sun.util.logging.resources.logging, locale en_US
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在我的应用程序中来自firebase崩溃报告.
其他详情
Manufacturer: HTC
Model: HTC 10
Android API: 24
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这是堆栈跟踪
java.util.logging.Logger$1.run (Logger.java:1385)
java.util.logging.Logger$1.run (Logger.java:1379)
java.security.AccessController.doPrivileged (AccessController.java:41)
java.util.logging.Logger.findSystemResourceBundle (Logger.java:1378)
java.util.logging.Logger.findResourceBundle (Logger.java:1425)
java.util.logging.Logger.setupResourceInfo (Logger.java:1523)
java.util.logging.Logger.<init> (Logger.java:266)
java.util.logging.Logger.<init> (Logger.java:261)
java.util.logging.LogManager$SystemLoggerContext.demandLogger (LogManager.java:734)
java.util.logging.LogManager.demandSystemLogger (LogManager.java:399)
java.util.logging.Logger.getPlatformLogger (Logger.java:474)
java.util.logging.LoggingProxyImpl.getLogger (LoggingProxyImpl.java:41)
sun.util.logging.LoggingSupport.getLogger (LoggingSupport.java:100)
sun.util.logging.PlatformLogger$JavaLoggerProxy.<init> (PlatformLogger.java:636)
sun.util.logging.PlatformLogger$JavaLoggerProxy.<init> (PlatformLogger.java:631)
sun.util.logging.PlatformLogger.<init> (PlatformLogger.java:246)
sun.util.logging.PlatformLogger.getLogger (PlatformLogger.java:205)
java.net.CookieManager.put (CookieManager.java:262)
okhttp3.JavaNetCookieJar.saveFromResponse (JavaNetCookieJar.java:47)
okhttp3.internal.http.HttpHeaders.receiveHeaders (HttpHeaders.java:182)
okhttp3.internal.http.BridgeInterceptor.intercept (BridgeInterceptor.java:95)
okhttp3.internal.http.RealInterceptorChain.proceed (RealInterceptorChain.java:92)
okhttp3.internal.http.RetryAndFollowUpInterceptor.intercept (RetryAndFollowUpInterceptor.java:120)
okhttp3.internal.http.RealInterceptorChain.proceed (RealInterceptorChain.java:92)
okhttp3.internal.http.RealInterceptorChain.proceed (RealInterceptorChain.java:67)
okhttp3.RealCall.getResponseWithInterceptorChain (RealCall.java:185)
okhttp3.RealCall.execute (RealCall.java:69)
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这是相关的Logger代码 …
有一个相关的问题,如何在 Android Studio 中增加字体大小?.
但它不会增加快速文档的字体大小。
<android.support.v7.widget.RecyclerView
android:id="@+id/recyclerView"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#ddd"
android:fadeScrollbars="true"
android:scrollbarSize="12dp"
android:orientation="vertical"
android:scrollbars="vertical"/>
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我正在测试5.1.1上的代码.改变android:scrollbarSize没有效果.我尝试增加和减少它,没有变化.
如何改变宽度?
android android-scrollbar android-recyclerview recyclerview-layout
class ClassSealer {
private:
friend class Sealed;
ClassSealer() {}
};
class Sealed : public ClassSealer
{
// ...
};
class FailsToDerive : public Sealed
{
// This class is capable of being instantiated
};
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以上未能封上课,但以下作品,为什么?
class ClassSealer {
private:
friend class Sealed;
ClassSealer() {}
};
class Sealed : public virtual ClassSealer
{
// ...
};
class FailsToDerive : public Sealed
{
// Cannot be instantiated
};
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这里发生了什么?虚拟继承在这里发挥了什么作用?
来自:http : //developer.android.com/guide/topics/manifest/activity-element.html
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这里的基本意图是什么?
#include <iostream>
using namespace std;
class myclass
{
public:
void fun()
{
cout<<"Having some fun"<<endl;
}
};
class spointer
{
myclass * mptr;
public:
spointer(myclass * m)
{
mptr=m;
}
myclass * operator->()
{
return mptr;
}
};
int main() {
// your code goes here
spointer s(new myclass);
s->fun();
return 0;
}
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当s->fun()调用时main,s->会返回指针myclass,但是如何在指针指向的对象fun()上调用myclass?
编辑:因为spointer::operator->返回指针myclass,为什么可以说s->fun(),而不是说s->->fun()或什么
#include <iostream>
using namespace std;
struct number
{
int value;
int pos;
public:
number(int a,int b)
{
value=a;
pos=b;
}
};
int main() {
// your code goes here
number(1,2);
return 0;
}
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在这种情况下,在哪里分配内存number(1,2)?在堆或堆栈上?我们如何验证它?
android ×5
c++ ×4
android-view ×1
heap ×1
imageview ×1
inheritance ×1
java ×1
memory ×1
namespaces ×1
okhttp ×1
okhttp3 ×1
pointers ×1
sealed ×1
stack ×1
xml-drawable ×1