小编Dri*_*ens的帖子

我正在练习考试,发现了一个我不明白的样本问题.

对于以下代码,找到输出的内容:

public class Test {

    private static int count = 0;

    public boolean equals(Test testje) {
        System.out.println("count = " + count);
        return false;
    }

    public static void main(String [] args) {
        Object t1 = new Test();
        Object t2 = new Test();
        Test t3 = new Test();
        Object o1 = new Object();

        ++count; t1.equals(t2);
        ++count; t1.equals(t3);
        ++count; t3.equals(o1);
        ++count; t3.equals(t3);
        ++count; t3.equals(t2);
    }
}

这段代码的输出是count = 4,但我不明白为什么.谁能帮我？

我需要输入一个句子并在该句子周围创建一个动态边框.边框需要输入宽度.当句子的长度高于给定的宽度时,必须打印一个新行,并且边框的高度必须改变.句子也必须集中在动态边界

我已经尝试过了:

sentence = input()
width = int(input())

length_of_sentence = len(sentence)

print('+-' + '-'*(width) + '-+')

for letter in sentence:
    print('| {0:^{1}} |'.format(letter, width - 4))

print('+-' + '-'*(width) + '-+')

但随后每个带有新行的字母都会打印出来,这不是我需要的.

一个很好的例子如下;

输入

sentence = "You are only young once, but you can stay immature indefinitely."
width = 26

产量

+----------------------------+
| You are only young once, b |
| ut you can stay immature i |
|         ndefinitely.       |
+----------------------------+

我有一个具有以下身体的班级成绩:

public class Grades {

    public static Grade getGrades(int marks) {
        if (marks < 10) {
            return Grade.FAILED;
        } else if (marks < 13) {
            return Grade.DISTINCTION;
        } else if (marks < 15) {
            return Grade.GREAT;
        } else {
            return Grade.GREATEST;
        }
    }

    public static void main(String args[]){
        System.out.println(getGrades(6));
    }
}

和枚举类:

public enum Grade {

    FAILED("F"),
    DISTINCTION("D"),
    GREAT("G"),
    GREATEST("G");


    private String code;

    Grade(String code){
        this.code = code;
    }

    public String getCode() {
        return code;
    }

}

我怎么能在打电话时避免使用if else构造getGrades(int …