小编E. *_* K.的帖子

IList<MyObject> ob1 = {new MyObject {Id = "1", Items = {BananaObject1, BananaObject2}}}  
IList<MyObject> ob2 = { new MyObject {Id = "1", Items = {BananaObject2, BananaObject3}},  
new MyObject {Id = "2", Items = {BananaObject3, BananaObject3}}}

我想合并2个列表,以便得到结果列表

IList<MyObject> ob2 = { new MyObject {Id = "1", Items = {BananaObject1, BananaObject2, BananaObject3}},
new MyObject {Id = "2", Items = {BananaObject3, BananaObject3}}}

因此,由于2个列表中第一个项目的ID相同,因此它们成为一个,并且其中一个属性被连接起来.
我可以做一个for循环来实现这一点,但我正在为此寻找一个整洁的最佳性能linq表达式.

谢谢