我一直在尝试使用以下json（testbootstraptable.json）文件创建dynamo数据库表：
{
"AttributeDefinitions": [
{
"AttributeName": "test1",
"AttributeType": "S"
},
{
"AttributeName": "test2",
"AttributeType": "S"
}
],
"TableName": "BOOTSTRAP_TEST_TBL",
"KeySchema": [
{
"AttributeName": "test1",
"KeyType": "HASH"
},
{
"AttributeName": "test2",
"KeyType": "RANGE"
}
],
"ProvisionedThroughput": {
"NumberOfDecreasesToday": 0,
"ReadCapacityUnits": 35,
"WriteCapacityUnits": 35
}
}
我已经尝试过多次基于Google搜索的不同变体形式，但始终出现以下错误：
Error parsing parameter 'cli-input-json': Invalid JSON: Expecting value: line 1 column 1 (char 0)
JSON received: testbootstraptable.json
AWS命令：
$ aws dynamodb create-table --cli-input-json testbootstraptable.json --region us-west-2
我正在尝试设置一个 wiremock 服务器来对一个进行 get http 调用的类进行单元测试。我能够成功设置模拟服务器，但是当我尝试存根请求时遇到错误。我对 WireMock 非常陌生，这似乎是一件非常简单的事情。请指教：
@Test
public void testMethod{
.........
WireMockServer wireMockServer = new WireMockServer(8089);
wireMockServer.start();
stubFor(get(urlEqualTo("/api/get-magic"))
.willReturn(aResponse()
.withHeader("Content-Type", "application/json")
.withBody("{\"currently\":{\"windSpeed\":12.34}}")));
........
wireMockServer.start();
}
堆栈跟踪：
com.fasterxml.jackson.core.JsonParseException: Unexpected character ('<' (code 60)): expected a valid value (number, String, array, object, 'true', 'false' or 'null')
at [Source: <html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/>
<title>Error 403 No valid crumb was included in the request</title>
</head>
<body><h2>HTTP ERROR 403</h2>
<p>Problem accessing /__admin/mappings. Reason:
<pre> No valid crumb was included in the …我正在使用一个故意混淆的代码,其中包含一个我无法理解的奇怪的typedef.任何人都可以解释以下typedef意味着什么:
typedef void (*p_t)(char* a1, char* a2, int a3);
后来主要使用如下:
int main(void) {
p_t p = &some_function;
p("foo", "bar", 42);
}