好的,所以我现在已经有一段时间了.我想要实现的是阻止人们创建在name ='name'字段中输入的相同名称.这是html代码.
<div class="fieldclass"><form action='/newlist.php' method='POST' id="formID">
Name Your Card <input class='ha' type='text' name='name'><p>
<input type='submit' value='create'/>
</form>
这是我的mysql页面.
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "christmas";
// Create connection
$dbhandle = mysqli_connect ($servername, $username, $password, $dbname) or die ("could not connect to database");
$selected = mysql_connect('christmas', $dbhandle);
$query = mysql_query("SELECT * FROM list WHERE name='$name'");
if(mysql_num_rows($query) > 0){
echo 'that name already exists';
}else{
mysql_query("INSERT INTO list(name, one , two, three, four, five, six, …我的文本表单不允许在输入字段中出现单个“”。我收到一个sql语法错误。有什么好的方法可以在我的文本字段中允许单撇号？
这是我的代码
html
<input class='what' type='text' name='one' required>
<textarea name='two' required></textarea>
<input type='submit'>
</form>
我的资料库
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "INSERT INTO whatsgood (one, two)
VALUES ('$one', '$two')";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
?>
任何帮助将不胜感激。谢谢！
当我的div上下滑动时,我尝试创建弹跳的每种方法都不起作用.任何帮助将不胜感激!
这是我的代码
$(document).ready(function() {
$('#button').click(function() {
$("#div").slideToggle();
$("#div").effect('bounce', 300);
});
});div#div {
width: 100px;
height: 100px;
background: #ccc;
border: 1px solid #000;
position: relative;
display: none;
top: 30px;
left: 0;
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button id="button">click</button>
<div id="div"></div>谢谢你的帮助!
我正在学习PHP并尝试if .. else更好地理解语句,所以我正在创建一个小测验.但是,我遇到了一个问题,我似乎不知道问题是什么.我的问题是每当我输入输入区域的年龄$yes时,即使我输入了错误的年龄,它也会每次都给我变量.
这是我到目前为止的代码:
我的html文件:
<form action="questions.php" method="post">
<p>How old is Kenny?<input></input>
<input type="submit" name="age" value="Submit"/>
</p></form>
我的php文件:
<?php
$age = 25;
$yes = "Awesome! Congrats!";
$no = "haha try again";
if ($age == 25){
echo "$yes";
}else{
echo "$no";
}
?>