小编Cas*_*sey的帖子

我有完整的URL作为字符串,但我想删除字符串开头的http://以很好地显示URL(例如:www.google.com而不是http://www.google.com)

有人可以帮忙吗？

我试图用下划线比较两个对象.

对象1(过滤器)

{
  "tuxedoorsuit":"tuxedoorsuit-tuxedo",
  "occasions":"occasions-wedding"
}

对象2(属性)

{
  "tuxedoorsuit":"tuxedoorsuit-tuxedo",
  "occasions":"occasions-wedding",
  "occasions":"occasions-prom",
  "product_fit":"product_fit-slim",
  "colorfamily":"colorfamily-black"
}

我想在对象2中找到对象1的所有项目时返回true.对此最好的下划线方法是什么？

我有一个下拉菜单(ul.sub-menu)里面的项目(ul.sub-menu> li),我想应用jQuery Masonry,但我的下拉绝对定位.有没有办法做到这一点,并保持我的父元素的绝对定位？

使用Javascript

jQuery("ul > li > ul.sub-menu").masonry({
  itemSelector: '.brick',
  columnWidth: 300
});

HTML

<ul>
<li id="menu-item-9451" class="menu-item menu-item-type-post_type menu-item-object-page menu-item-9451"><a href="/solutions/" >Solutions</a>
<ul class="sub-menu">
<li id="menu-item-9458" class="brick"><a href="/solutions/internal-social-software/" >Internal Social Software</a></li>
<li id="menu-item-9457" class="brick"><a href="/solutions/video-content-managment/" >Video Content Managment</a></li>
<li id="menu-item-9456" class="brick"><a href="/solutions/enterprise-content-management/" >Enterprise Content Management</a></li>
<li id="menu-item-9455" class="brick"><a href="/solutions/secure-file-sharing/" >Secure File Sharing</a></li>
<li id="menu-item-9454" class="brick"><a href="/solutions/redaction-and-document-viewing/" >Redaction and Document Viewing</a></li>
<li id="menu-item-9453" class="brick"><a href="/solutions/real-time-business-intelligence/" >Real Time Business Intelligence</a></li>
<li id="menu-item-9452" class="brick"><a href="/solutions/mobile-enterprise-applications/" >Mobile Enterprise Applications</a></li>
</ul>
</li>
</ul>