小编luc*_*cas的帖子

我从网页(http://www.opensolaris.org/os/community/on/flag-days/all/)中提取一些代码,如下所示,

<tr class="build">
  <th colspan="0">Build 110</th>
</tr>
<tr class="arccase project flagday">
  <td>Feb-25</td>
  <td></td>
  <td></td>
  <td></td>
  <td>
    <a href="../pages/2009022501/">Flag Day and Heads Up: Power Aware Dispatcher and Deep C-States</a><br />
    cpupm keyword mode extensions - <a href="/os/community/arc/caselog/2008/777/">PSARC/2008/777</a><br />
    CPU Deep Idle Keyword - <a href="/os/community/arc/caselog/2008/663/">PSARC/2008/663</a><br />
  </td>
</tr>

并且它中有一些相对的url路径,现在我想用正则表达式搜索它并用绝对url路径替换它们.因为我知道urljoin可以做那样的替换工作,

>>> urljoin("http://www.opensolaris.org/os/community/on/flag-days/all/",
...         "/os/community/arc/caselog/2008/777/")
'http://www.opensolaris.org/os/community/arc/caselog/2008/777/'

现在我想知道如何使用正则表达式搜索它们,最后将代码转换为,

<tr class="build">
  <th colspan="0">Build 110</th>
</tr>
<tr class="arccase project flagday">
  <td>Feb-25</td>
  <td></td>
  <td></td>
  <td></td>
  <td>
    <a href="http://www.opensolaris.org/os/community/on/flag-days/all//pages/2009022501/">Flag Day and Heads Up: Power Aware Dispatcher …

我知道cout和printf今天有缓冲区,据说缓冲区有点像堆栈,从右到左得到cout和printf的输出,然后从顶部到bottem将它们(到控制台或文件)放出.像这样,

a = 1; b = 2; c = 3;
cout<<a<<b<<c<<endl;
buffer?|3|2|1|<-   (take “<-” as a poniter)

output?|3|2|<-     (output 1)
        |3|<-       (output 2)
        |<-         (output 3)

然后我写下面的代码,

#include <iostream> 
using namespace std; 
int c = 6;
int f() 
{   
    c+=1; 
    return c; 
} 

int main() 
{ 
     int i = 0; 
     cout <<"i="<<i<<" i++="<<i++<<" i--="<<i--<<endl; 
     i = 0;
     printf("i=%d i++=%d i--=%d\n" , i , i++ ,i-- );

     cout<<f()<<" "<<f()<<" "<<f()<<endl; 
     c = 6;
     printf("%d %d %d\n" , f() , f() ,f() …

我知道cout几天前有缓冲区,当我google它时,据说缓冲区有点像堆栈并从右到左获取cout和printf的输出,然后将它们输出(到控制台或文件) )从顶部到bottem.像这样,

a = 1; b = 2; c = 3;
cout<<a<<b<<c<<endl;
buffer?|3|2|1|<-   (take “<-” as a poniter)

output?|3|2|<-     (output 1)
        |3|<-       (output 2)
        |<-         (output 3)

然后我写下面的代码,

#include <iostream> 
using namespace std; 
int c = 6;
int f() 
{   
    c+=1; 
    return c; 
} 

int main() 
{ 
     int i = 0; 
     cout <<"i="<<i<<" i++="<<i++<<" i--="<<i--<<endl; 
     i = 0;
     printf("i=%d i++=%d i--=%d\n" , i , i++ ,i-- );

     cout<<f()<<" "<<f()<<" "<<f()<<endl; 
     c = 6;
     printf("%d %d %d\n" , f() , f() …