小编Nir*_*nae的帖子

我是PDO的新手,编写更新查询:

$sql = "UPDATE `users` 
           SET(`uname` = :uname,
               `role` = :role,
               `fname` = :fname,
               `email` = :email,
               `mobile1` = :mobile1,
               `mobile2` = :mobile2,
               `education` = :education,
               `division` = :division,
               `district` = :district,
               `sub_district` = :sub_district,
               `address` = :address,
               `looking_for` = :looking) 
         WHERE `id` = :id";

            //$sql = "UPDATE `users` SET(`uname`=?,`role`=?,`fname`=?,`email`=?,`mobile1`=?,`mobile2`=?,`education`=?,`division`=?,`district`=?,`sub_district`=?,`address`=?,`looking_for`=?) WHERE `id`=?";
            $st = $conn->prepare($sql);
            //$res['sql'] = $st->queryString;
            $params = array(
                ':uname' => $uname, 
                ':role' => $role, 
                ':fname' => $fname, 
                ':email' => $email, 
                ':mobile1' => $mobile1, 
                ':mobile2' => $mobile2, 
                ':education' …

我加入行throught一个<table>用foreach.

在某些时候,我希望一个单元格具有基于PHP中计算的百分比的灰色背景.

例如:50%意味着细胞背景的一半是灰色的,其余的将保持空白 33,33%= 1/3的背景等.

我遇到的问题是<td>被任何其他div拉伸的文本,如果我将颜色应用于<td>我将稍后覆盖文本等.

这是代码:

$percent = 1/3; // For example
$percent_friendly = number_format( $percent * 100, 2 ); //This will return 33.33

echo '<td>'.$percent_friendly.' %
    <div style="background-color: grey"> // So I want the grey to fill 33.33% of the space
    </div>
    <div style="background-color: white">
    </div>
</td>';

和迄今为止应用的样式:

table {
    margin-left:auto; 
    margin-right:auto;
    font-size:18px;
}

table, th, td {
    text-align: center;
    border: 1px solid black;
    position:relative;
}

我必须遗漏一些东西,但CSS真的不是我的东西,任何解释或帮助将不胜感激.

我有一个数组JavaScript和一个字符串:

var pool1 = ['ca','cahier','cartable','carte','cartographe','canape'];
var key1 = 'car';

我想要做的是,从数组中删除所有不包含的值key1.

为此,我写了这个函数:

function searchInPool(key, pool){
    for (i = 0; i < pool.length; i++) {
        var index = pool[i].indexOf(key);
        if (index > -1) {
            pool.splice(index, 1);
        }
    }
    return pool;
}

它似乎有效,但最终结果给了我:

["cartable", "carte", "cartographe", "canape"]

它已成功删除ca,cahier但canape不应该在这里,因为它不包含car任何人可以解释我从我的函数中写的东西误解了什么？

预期的最终结果是:

["cartable", "carte", "cartographe"]

非常感谢

我想改变我的阵列,我怎样才能做出这种改变.

Array ( [0] => 53720 [1] => Array( ['Build Quality'] => 1=>10, 2=>9, 3=>7 ['Versatality'] => 1=>9, 2=>8, 3=>7 ['value'] => 1=>8, 2=>6, 3=>5 ) );

至:

Array ( 53720 =>['Build Quality' => [1=>10, 2=>9, 3=>7], 'Versatality' => [1=>9, 2=>8, 3=>7], 'value' => [1=>8, 2=>6, 3=>5] ] );

function get_array(){

  $factor = array([0] => 'Build Quality' [1] => 'Versatality' [2] => 'Value');  
  $rank = array([0] => 1=>10,2=>9,3=>7 [1] => 1=>9,2=>8,3=>7 [2] => 1=>8,2=>6,3=>5);  
  $assoc_array = array_combine($factor, $rank);
  $post_id = …