小编Jan*_*ane的帖子

使用Java配置的Spring LDAP

我正在关注Spring LDAP项目示例,并尝试将xml配置转换为Java Configuration.

我正在尝试在LDAP服务器上执行CRUD操作.

我能够弄清楚以下几点,

这是应用程序的xml配置,我希望将其转换为Java Config.

<context:property-placeholder location="classpath:/ldap.properties"
        system-properties-mode="OVERRIDE" />
    <context:annotation-config />

    <ldap:context-source id="contextSource" password="${sample.ldap.password}"
        url="${sample.ldap.url}" username="${sample.ldap.userDn}" base="${sample.ldap.base}" />

    <ldap:ldap-template id="ldapTemplate"
        context-source-ref="contextSource" />

    <!-- This will scan the org.springframework.ldap.samples.useradmin.domain 
        package for interfaces extending CrudRepository (in our case, LdapRepository), 
        automatically creating repository beans based on these interfaces. -->
    <ldap:repositories base-package="com.cazysystems.appstore.model" />

    <!-- This one will never be referenced directly, but the ldap:repositories 
        tag will make sure it will be 'wired in', because …
Run Code Online (Sandbox Code Playgroud)

java spring spring-ldap spring-boot spring-java-config

5
推荐指数
1
解决办法
1万
查看次数

无法退出AWS CLI hep页面

安装后awscli.我尝试了文档中提到的help命令,

$ aws help
Run Code Online (Sandbox Code Playgroud)

当我这样做时,我可以全屏看到以下页面.似乎无法摆脱它.

我试过Ctrl+C,它不会回到我的Ubuntu命令行.

AWS()                                                                    AWS()



NAME
       aws -

DESCRIPTION
       The  AWS  Command  Line  Interface is a unified tool to manage your AWS
       services.

SYNOPSIS
          aws [options] <command> <subcommand> [parameters]

       Use aws command help for information on a  specific  command.  Use  aws
       help  topics  to view a list of available help topics. The synopsis for
       each command shows its parameters and their usage. Optional  parameters
       are shown in square brackets.
Run Code Online (Sandbox Code Playgroud)

amazon-s3 amazon-web-services aws-cli

3
推荐指数
2
解决办法
3939
查看次数

Spring JPA,MySQL-无法写入内容:通过引用链无限递归StackOverflowError

我想知道我在这里做错了什么,因为我已经完成了加载类型,它不是递归的.但是我收到以下错误.当我尝试从访问对象访问getServerRequest()方法时.

WARN 6511 --- [nio-8080-exec-2] .wsmsDefaultHandlerExceptionResolver:写入HTTP消息失败:org.springframework.http.converter.HttpMessageNotWritableException:无法写入内容:无限递归(StackOverflowError)(通过参考链:com. biscoind.domain.ServerRequest [ "访问"] - > org.hibernate.collection.internal.PersistentBag [0] - > com.biscoind.domain.Visit [ "请求"] - > com.biscoind.domain.ServerRequest ["访问"] - > org.hibernate.collection.internal.PersistentBag [0] - > com.biscoind.domain.Visit [" 请求 "] - > com.biscoind.domain.ServerRequest [" 访问"] - > org.hibernate作为. collection.internal.PersistentBag [0] - > com.biscoind.domain.Visit [ "请求"] - > com.biscoind.domain.ServerRequest [ "访问"] - > org.hibernate.collection.internal.PersistentBag [0] - > com.biscoind.domain.Visit [ "请求"] - > com.biscoind.domain.ServerRequest [ "访问"] - > org.hibernate.collection.internal.PersistentBag [0] - > com.biscoind.domain.访问[ "请求"] - > com.biscoind.domain.ServerRequest [ "访问"] - …

java spring hibernate jpa

2
推荐指数
1
解决办法
5645
查看次数