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如何从jquery ajax调用访问数据返回.$ .ajax()之外.

//Reloads the inital page
function jobexist( jobname )
{
   var dataString = 'jobname=' + jobname;
   var found = false;

   $.ajax(
   {
      type: 'POST',
      url: "/genode/jobs/jobexist.m",
      data: dataString,
      dataType: 'json',
      success: function(data)
      {
         alert("Passed");
         if( data.result == 0 )
         {
            found = true;
          }else{  
            found = false; 
          }
      },
      error: function( data )
      {
         alert("Login Failed");
         return -1; //alert(data);
      }
   });

   if( found == true )
   {
       alert("found!")'
       return true;
   }else{
       alert("not found!");
       return false;
    }
}



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