小编sea*_*idk的帖子

几天来一直有这个问题.我正在使用简单的用户名和密码登录屏幕,并将所有内容存储在数据库中.我需要检查用户名和密码是否匹配,并查看帐户是否已激活(0或1).我一直遇到这个问题,似乎无法让它正常工作.任何帮助表示赞赏.

DB Mysql

    private void loginButton_Click(object sender, EventArgs e)
        {
            AdamPanel blarg = new AdminPanel();
            string pass, user;
            string password = "";
            string username = "";

            user = usernameBox.Text;
            pass = passwordBox.Text;           
            DataSet bb = new DataSet();

            string connectionString = "datasource=stuff;database=users";
            MySqlConnection mysql = new MySqlConnection(connectionString);
            MySqlDataAdapter adapter = new MySqlDataAdapter();

            adapter.SelectCommand = new MySqlCommand("SELECT * FROM RegularUsers WHERE Username = '" + user + "' AND Password = '" + pass + "'", mysql);
            adapter.Fill(bb);

            if(bb.HasRows)
                blarg.Show();
            return 0; …

那么为游戏编写登录检查器,并从C#切换到java.问题是我使用旧代码作为例子,但是通过从连接创建语句来继续解决这个问题.我得到"找不到"createStatement()符号".是否有新的方法来执行SQL语句或是否有其他错误？

这是源代码.

import java.sql.*;

public class SQLCheck {

    public Connection con;
    public void connect(){
        String host = "somewhereoutthere";
        String username = "stuff";
        String pass = "haclmolg";
        String db = "users";

        try{
            Class.forName("com.mysql.jdbc.Driver");
            String connectionUrl = "jdbc:mysql://"+host+"/"+db+"?";
            con = (Connection) DriverManager.getConnection(connectionUrl,username,pass);
            System.out.println("Server: Connected to MYSQL");
        } catch(SQLException e){
            System.out.println("Server: SQL EXECEPTION: " + e.toString());
        } catch (ClassNotFoundException cE){
            System.out.println("Server: Class not found: " + cE.toString());
        }
    }
    boolean checkLogin(String userName, String password){
        boolean correct = false;

        Statement s = con.createStatement();
    } …