我正在使用数据库路由器,因此我的应用程序有两个数据库.一个数据库用于默认的django数据,另一个数据库.
在我的管理员中,我已覆盖该save_model函数以保存created_by变量,但我无法执行此操作.
Cannot assign "<User: testuser>": the current database router prevents this relation.
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数据库路由:
from django.conf import settings
class DatabaseAppsRouter(object):
def db_for_read(self, model, **hints):
"""Point all read operations to the specific database."""
if settings.DATABASE_APPS_MAPPING.has_key(model._meta.app_label):
return settings.DATABASE_APPS_MAPPING[model._meta.app_label]
return None
def db_for_write(self, model, **hints):
"""Point all write operations to the specific database."""
if settings.DATABASE_APPS_MAPPING.has_key(model._meta.app_label):
return settings.DATABASE_APPS_MAPPING[model._meta.app_label]
return None
def allow_relation(self, obj1, obj2, **hints):
"""Allow any relation between apps that use the same database."""
db_obj1 = settings.DATABASE_APPS_MAPPING.get(obj1._meta.app_label)
db_obj2 = …Run Code Online (Sandbox Code Playgroud) 我试图打印一个Long in Binary,但它一直在切断0.有没有办法强迫它显示所有位?
这是我的代码:
long l = 1;
System.out.println(Long.toBinaryString((long)l));
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如上所述返回仅1由于删除0'si希望维护:
0000 0000 0000 0000 0000 0000 0000 0001
提前致谢.
我临时讨厌的解决方案:
public String fillZeros(Long value)
{
String str = Long.toBinaryString((long) value);
String temp;
temp = str;
while(temp.length() < 32) {
temp = "0" + temp;
}
return temp;
}
Run Code Online (Sandbox Code Playgroud) 我试图将两个图像复制到一个大图像,但不幸的是我无法插入只有1个图像以下尝试:
void showTwoImages(Mat imageOne, Mat imageTwo, string title) {
int totalCol = imageOne.cols+imageTwo.cols;
int totalRow = imageOne.rows;
Mat totalImage(Size(totalCol, totalRow), 8, 3);
imageOne.copyTo(totalImage(Rect(0,0,imageOne.cols, imageOne.rows)));
viewImage(totalImage, title);
}
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我的错误:

不幸的是我没有从XCode中获得特定的错误,但引用汇编程序代码,所以我无法确定发生的错误.
我已经使用与rabbitmq一起运行的Celery设置了Django。
我在我的项目中实现了以下示例:http://docs.celeryproject.org/en/master/django/first-steps-with-django.html
当我在两个终端窗口中运行简单测试时,结果如下:
# Terminal 1
>>> from Exercise.tasks import *
>>> result = add.delay(2,3)
>>> result
<AsyncResult: e6c92297-eea2-4f99-8902-1446ac74a6bb>
>>> result.ready()
False
# Terminal 2
$ celery -A Website3 worker -l info
[2014-10-02 14:39:59,269: INFO/MainProcess] Received task: Exercise.tasks.add[464249dd-ab89-4099-badd-9190a147310f]
[2014-10-02 14:39:59,271: INFO/MainProcess] Task Exercise.tasks.add[464249dd-ab89-4099-badd-9190a147310f] succeeded in 0.0010875929147s: 5
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显然数据已完成,但我无法接收该数据。
我在这里做错了什么?
我已经在React中实现了一个小测试应用程序来通过AJAX获取数据,但它没有按照意图工作,因此我得到以下错误:
Uncaught TypeError: Cannot read property 'map' of undefinedInline JSX script
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代码如下:
<div id="content"></div>
<script type="text/jsx">
var Bodypart = React.createClass({
render: function() {
return (
<div>
{this.props.name}
</div>
)
}
})
var BodypartList = React.createClass({
getInitialState: function() {
return {data: []};
},
componentWillMount: function() {
$.ajax({
url: this.props.url,
dataType: 'json',
success: function(data) {
this.setState({bodyparts: data});
}.bind(this),
error: function(xhr, status, err) {
console.error(this.props.url, status, err.toString());
}.bind(this)
});
},
render: function() {
var bodypartItems = this.state.bodyparts.map(function (bodypart) {
return (
<Bodypart
name={bodypart.name} …Run Code Online (Sandbox Code Playgroud) 我目前正在解析XML,但我不太确定如何解析"message"的"status"属性:
<message status="test"> <text>sometext</text> <msisdn>stuff</msisdn> </message>
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这是代码,我已经切断了一切不必要的东西:
NodeList nodeLst = doc.getElementsByTagName("message");
for (int s = 0; s < nodeLst.getLength(); s++) {
Node fstNode = nodeLst.item(s);
if (fstNode.getNodeType() == Node.ELEMENT_NODE) {
Element fstElmnt = (Element) fstNode;
NodeList numberNmElmntLst = fstElmnt
.getElementsByTagName("msisdn");
Element numberNmElmnt = (Element) numberNmElmntLst.item(0);
NodeList numberNm = numberNmElmnt.getChildNodes();
String phoneNumber = ((Node) numberNm.item(0))
.getNodeValue().substring(2);
NodeList txtNmElmntLst = fstElmnt
.getElementsByTagName("text");
Element txtNmElmnt = (Element) txtNmElmntLst.item(0);
NodeList txtNm = txtNmElmnt.getChildNodes();
String text = ((Node) txtNm.item(0)).getNodeValue();
NodeList rcvNmElmntLst = fstElmnt
.getElementsByTagName("received");
Element …Run Code Online (Sandbox Code Playgroud) 我很好奇这个程序是否可以以更加优雅和清洁的方式取得成功?
foreach (MediaTitle item in mediaTitleCollection)
{
if (item is FilmMedia)
{
FilmMedia tempItem = (FilmMedia) item;
sum += tempItem.Playtime;
}
}
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提前致谢.
现在数据在数据库中看起来像这样:
Hej [indtaster_navn] <br> <br>我forbindelse mednogetpåændringafxxxxxx er der behovforopfølgningpå:<br> <br> xxxx <br> - xxxx <br> - xxxx <br> <br> Jeg vil gerne has enlapbagemelding,nårduharsetpåcaborstående.<br/> <br/> Venlig hilsen <br/> [behandler_navn] <br/> TestGuy <br/> <br/> [lokal_tlf] - lokal <br > 00 00 00 00 - telefon <br> [behandler_email] <br> <br>这个S <br> Something <br> Transformer 1234 <br> 3434 BubbleJ <br> <br>
所以我在发送邮件时有以下代码,重要的是要注意我使用html_entity_decode:
$config['mailtype'] = 'html';
$config['priority'] = 1;
$config['charset'] = 'utf-8';
$this->email->initialize($config);
$this->email->from($this->auth_data->user_email, $this->auth_data->user_firstname . ' ' . $this->auth_data->user_lastname);
$this->email->reply_to($this->auth_data->user_email, $this->auth_data->user_firstname …Run Code Online (Sandbox Code Playgroud) 我有一个由两个人组成的模型ForeignKeys.我只对解析内容感兴趣ForeignKeys,所以我使用的是depth变量,它基本上给了我用FK引用的表的所有列.有没有办法选择应该包含哪些列?
class SomeSerializer(serializers.ModelSerializer):
class Meta:
model = MyAwesomeModel
fields = ('id', 'fk_one','fk_two')
depth = 1
Run Code Online (Sandbox Code Playgroud) 我让芹菜与 django-celery 一起运行,基本上我无法弄清楚为什么芹菜工人在任务停止后保留内存?
是否有可以在特定任务结束时释放内存的参数?
我正在运行 Celery 3.1.16 和 rabbitmq 作为代理。
来自 ps 辅助:
1000 6411 0.3 3.8 117288 39564 pts/0 S+ 12:44 0:00 /usr/bin/python /usr/local/bin/celery -A Website3 worker -l info
1000 6454 6.7 6.1 143660 62760 pts/0 S+ 12:44 0:12 /usr/bin/python /usr/local/bin/celery -A Website3 worker -l info
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数据保持这样,直到我杀死工人并重新启动它。
有没有可以设置释放内存的参数?
django ×4
celery ×2
java ×2
c# ×1
codeigniter ×1
django-admin ×1
django-forms ×1
dom ×1
email ×1
encoding ×1
javascript ×1
opencv ×1
php ×1
python ×1
rabbitmq ×1
reactjs ×1
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