这是ajax
$(".urut").change(function() {
$.ajax({
url: "<?php echo base_url(); ?>categories/brand/<?= $link_brand; ?>?l=<?= $l; ?>&h=<?= $h; ?>&city=<?= $city; ?>&city_name=<?= $city_name; ?>&ket=view",
type: "POST",
data: "urut=" + $(".urut").val(),
success: function(data) {
$("#result").html(data);
}
})
})Run Code Online (Sandbox Code Playgroud)
这是有效的,但我想要更改网址,因为我有很多参数,当然还有data: "urut="+$(".urut").val(),参数.
这是我的in_array代码
$array = array('a', 'b', 'c');
if(in_array(array('p', 'c'), $array)){
echo "found";
}else{
echo "not found";
}
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它返回未找到,但实际上我希望它返回found,因为有一个值匹配c。
当我收到传入商品数据(belongsTo)时,产品数据始终返回null。
这是我的产品型号:
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\SoftDeletes;
class Product extends Model
{
use SoftDeletes;
protected $guarded = [
'id', 'created_at', 'updated_at', 'deleted_at',
];
public function transaction_details()
{
return $this->hasMany('App\Transaction_detail');
}
public function incoming_goods()
{
return $this->hasMany('App\Incoming_good');
}
}
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这是我的Incoming_good模型:
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
class Incoming_good extends Model
{
protected $guarded = [
'id', 'created_at', 'updated_at',
];
public function product()
{
return $this->belongsTo('App\Product');
}
}
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这是我对这两个表的迁移:
产品表迁移:
<?php
use Illuminate\Support\Facades\Schema;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;
class CreateProductsTable extends Migration …Run Code Online (Sandbox Code Playgroud) 这是我的数组:
$myArray = array(
array("name"=>"Andrea", "Age"=>17),
array("name"=>"Tresna", "Age"=>20),
array("name"=>"Aria", "Age"=>12)
);
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我想按数组中的值过滤该多数组。这是我的过滤器:
$filter = array("Andrea", "Aria");
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所以结果一定是这样的:
$newArray = array(
array("name"=>"Andrea", "Age"=>17),
array("name"=>"Aria", "Age"=>12)
);
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怎么办?
php ×4
arrays ×2
ajax ×1
array-filter ×1
javascript ×1
jquery ×1
laravel ×1
mysql ×1
relationship ×1