我在Instagram上发布的不是方形照片 https://instagram.com/p/7M7aBoNTcM/
通过Instagram api使用https _ // api.instagram.com/v1/media/1061415553965831926_2141618404?access_token=Token尝试获取所有照片,并为该图像提供下一个standard_resolution网址:https://scontent.cdninstagram.com/hphotos- xfa1 // // t51.2885-15 // s640x640 // sh0.08 E35 // 11821940_708988202567623_81870409_n.jpg
没有用于裁剪的参数,但是我在图像的顶部和底部得到了带有白线的图像.
为什么在Instagram的网站上发送我的图像(矩形),但api返回带有白线的正方形?
如何在没有白线的情况下发布不是方形图片?
我是Python和Linux的新手,我需要帮助,我尝试使用matplotlib以下列方式显示一个简单的图:
from matplotlib import pyplot as plt
plt.plot([5,6,7,8], [7,3,8,3])
plt.show()
Run Code Online (Sandbox Code Playgroud)
但是,当我运行时python3 test.py
,我得到以下输出:
/usr/local/lib/python3.4/dist-packages/matplotlib/backends/backend_gtk3agg.py:18: UserWarning: The Gtk3Agg backend is known to not work on Python 3.x with pycairo. Try installing cairocffi.
"The Gtk3Agg backend is known to not work on Python 3.x with pycairo. "
Traceback (most recent call last):
File "/usr/local/lib/python3.4/dist-packages/matplotlib/backends/backend_gtk3agg.py", line 69, in on_draw_event
buf, cairo.FORMAT_ARGB32, width, height)
NotImplementedError: Surface.create_for_data: Not Implemented yet.
Traceback (most recent call last):
File "/usr/local/lib/python3.4/dist-packages/matplotlib/backends/backend_gtk3agg.py", line 69, in on_draw_event
buf, cairo.FORMAT_ARGB32, width, …
Run Code Online (Sandbox Code Playgroud)