小编Muh*_*mar的帖子

我有两个选择声明

1

select Start_Date
    from table1  where Start_Date not in (
    select End_Date
    from table1)

2

 select End_Date from table1
    where End_Date not in (
        select Start_Date
            from table1
        )

我想在我使用union时将不同列中的两个select语句组合在一起它给我一个列,其中两个查询的结果我希望每个查询结果在不同的列中,但是当我使用内部联接时

select a.End_Date , b.Start_Date from
( select End_Date from table1
where End_Date not in (
select Start_Date
from table1
) ) a

join

(select Start_Date
from table1 where Start_Date not in (
select End_Date
from table1)
) b
on 1=1

它给我的结果每个记录重复四次帮助我下一步做什么？

我已经定义了与投资组合的用户关系,但它让我的用户模型为null

class User extends Model implements AuthenticatableContract,
                                    AuthorizableContract,
                                    CanResetPasswordContract
{
    use Authenticatable, Authorizable, CanResetPassword;
    protected $table = 'users';
    protected $fillable = ['name', 'email', 'password'];
    protected $hidden = ['password', 'remember_token'];

    public function portfolio()
    {
        $this->hasMany('App\Portfolio');
    }

}

我的投资组合模型是

class Portfolio extends Model
{

    protected $fillable = ['user_id', 'ptitle', 'pdate','pedate','purl','languages','pdes','attachments'];

    public function user()
    {
        $this->belongsTo('App\User');
    }
    public function attachments()
    {
        $this->hasMany('App\Attachment');
    }
}

我已经在迁移中定义了外键,我的迁移代码是

public function up()
    {
        Schema::create('portfolios', function (Blueprint $table) {
            $table->increments('id');
            $table->integer('user_id')->unsigned();
            $table->string('ptitle');
            $table->timestamps();
            $table->foreign('user_id')
                   ->references('id')
                    ->on('users')
                    ->onDelete('cascade');
        }); …