小编Jef*_*mas的帖子

我有2个下拉列表,我想这样做,当有人从dropdown1中选择例如值2时,dropdown2自动更改为值2.这是否可以使用jquery？

<select id="dropdown1">
 <option value="1">Item1</option>
 <option value="2">Item2</option>
 <option value="3">Item3</option>
</select>

<select id="dropdown2">
 <option value="1">Item1</option>
 <option value="2">Item2</option>
 <option value="3">Item3</option>
</select>

我有一个CSS manu,我正在使用子菜单.我想知道如何添加一个子子菜单.例如,我将鼠标悬停在主菜单项上并弹出子菜单,然后将鼠标悬停在子菜单项上,弹出另一个子菜单.这是我现在使用的JS小提琴:

http://jsfiddle.net/PrinceofVegas/Dg3yQ/4/

这是我正在使用的CSS:

.menu{
    border:none;
    border:0px;
    margin:0px;
    padding:0px;
    font: 67.5% "Lucida Sans Unicode", "Bitstream Vera Sans", "Trebuchet Unicode MS", "Lucida Grande", Verdana, Helvetica, sans-serif;
    font-size:18px;
    font-weight:bold;
}
.menu ul{
    background:#006633;
    height:35px;
    list-style:none;
    margin:0;
    padding:0;
}
.menu li{
    float:left;
    padding:0px;
}
.menu li a{
    background:#006633 url("../images/seperator.gif") bottom right no-repeat;
    color:#ffffff;
    display:block;
    font-weight:normal;
    line-height:35px;
    margin:0px;
    padding:0px 25px;
    text-align:center;
    text-decoration:none;
}
.menu li a:hover, .menu ul li:hover a{
    background: #003f20 url("../images/hover.gif") bottom center no-repeat;
    color:#FFFFFF;
    text-decoration:none;
}
.menu li ul{
    background:#006633;
    display:none; …

现在我正在使用此代码从我的服务器获取电子邮件.

<?php
$imap = imap_open($server, $username, $password) or die("Connection Error");
$message_count = imap_num_msg($imap);
for ($i = 1; $i <= $message_count; ++$i){

    $header = imap_header($imap, $i);
    //print_r($header);

    $email[$i]['fromaddress'] = $header->from[0]->personal;
    $email[$i]['to'] = $header->to[0]->mailbox;
    $email[$i]['subject'] = $header->subject;
    $email[$i]['message_id'] = $header->message_id;
    $email[$i]['date'] = $header->udate;

    $from = $email[$i]['fromaddress'];
    $from_email = $email[$i]['from'];
    $to = $email[$i]['to'];
    $subject = $email[$i]['subject'];

    echo $from_email . '</br>';
    echo $to . '</br>';
    echo $subject . '</br>';

    imap_setflag_full($imap, $i, "\\Seen");
    imap_mail_move($imap, $i, 'Trash');
}

imap_close($imap);

?>

我希望能够获取附件并将​​它们保存到我的服务器上的文件夹中,并在输出中显示指向这些附件的链接.实现这一目标的最简单方法是什么？

我正在构建一个Android应用程序,我有一个警告,但没有引起任何问题,当我看到一个警告,我喜欢至少知道是什么原因导致它.该应用使用webview.

以下是导致警告的代码.

ImageView viewSplash;
WebView mWebView;
@Override
public void onCreate(Bundle icicle) {

    super.onCreate(icicle);
    setContentView(R.layout.main);

    viewSplash = (ImageView) findViewById(R.id.splash);
    mWebView = (WebView) findViewById(R.id.webview);
    mWebView.getSettings().setJavaScriptEnabled(true);
    mWebView.getSettings().setGeolocationEnabled(true);
    mWebView.loadUrl("http://www.google.com");
    mWebView.setWebViewClient(new WebViewtest(){
        @Override
        public void onPageFinished(WebView View, String url)
        {
            viewSplash.setVisibility(View.GONE);

                }
    });
}

这是错误:

应以静态方式访问静态字段View.GONE.

我正在访问Google Plus API,这是返回的结果之一:

{
 "nextPageToken": "Ci8I0bJLEie2uAPcvrABl96xAdaVqgO93LADn_6ABO2vgwXqpbAFoNmEBsHCpwgYAgovCJXLThInn-8054qFArGHmQKtp-gD_r6-BOqlsAW-7uAGjO7QB4HbngqEoKkLGAEQj5e7jAUY8sK7jAUiAA",
 "items": [
  {
   "id": "z13rwjqhyqzve5tgq04cdxfyfzqtgfszfcw",
   "url": "https://plus.google.com/104261567553968048744/posts/SDs5inGSpEi",
   "actor": {
    "displayName": "Evan Parker",
    "url": "https://plus.google.com/104261567553968048744"
   },
   "verb": "post",
   "object": {
    "attachments": [
     {
      "objectType": "photo",
      "displayName": "#throughglass",
      "id": "104261567553968048744.5876882440165641794",
      "content": "s_00d2c678-b686-49db-9666-a55292cbe59b-0",
      "url": "https://plus.google.com/photos/104261567553968048744/albums/5876882440813674497/5876882440165641794?authkey=CM3iyKyWoa7gcA",
      "image": {
       "url": "https://lh5.googleusercontent.com/-aI28I0V0geM/UY7hcTjNzkI/AAAAAAABzYw/8MxNghGljew/w497-h373/s_00d2c678-b686-49db-9666-a55292cbe59b-0",
       "type": "image/jpeg",
       "height": 373,
       "width": 497
      },
      "fullImage": {
       "url": "https://lh5.googleusercontent.com/-aI28I0V0geM/UY7hcTjNzkI/AAAAAAABzYw/8MxNghGljew/s0-d/s_00d2c678-b686-49db-9666-a55292cbe59b-0",
       "type": "image/jpeg",
       "height": 1888,
       "width": 2560
      }
     }
    ]
   }
  },
  {
   "id": "z12zh1gopsqyep5ox04cef0rwqrtsl1ai54",
   "url": "https://plus.google.com/117367546931116283373/posts/THnmvu6e9FT",
   "actor": {
    "displayName": "Max Braun",
    "url": "https://plus.google.com/117367546931116283373"
   },
   "verb": "post",
   "object": …

我有一个企业输入他们的时间的下拉菜单.每天都有一个下拉列表,ID为hours_dayname_open和hours_dayname_closed.我还有一个复选框,将其标记为已关闭.如果选中它,我使用以下jQuery来禁用下拉列表:

$("#closed_monday").click( function(){
    if($(this).is(':checked')){
        $("#hours_monday_open").attr("disabled", true);
        $("#hours_monday_closed").attr("disabled", true);
    }else{
        $("#hours_monday_open").attr("disabled", false);
        $("#hours_monday_closed").attr("disabled", false);
    }
});

但是,选中该复选框时,仅禁用/启用开放时间...关闭的下拉列表似乎被忽略.