小编Sat*_*dev的帖子

如何使用节点js运行html文件

我有一个简单的html页面,角度js如下:

    //Application name
    var app = angular.module("myTmoApppdl", []);

    app.controller("myCtrl", function ($scope) {
        //Sample login function
        $scope.signin = function () {
            var formData =
                    {
                        email: $scope.email,
                        password: $scope.password
                    };
        console.log("Form data is:" + JSON.stringify(formData));
    };
});

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HTML文件:

<html>
    <head>
        <link href="bootstrap.min.css" rel="stylesheet" type="text/css"/>
    </head>

    <body ng-app="myTmoApppdl" ng-controller="myCtrl">
        <div class="container">
            <div class="form-group">
                <form class="form" role="form" method="post" ng-submit="signin()">
                    <div class="form-group col-md-6">
                        <label class="">Email address</label>
                        <input type="email" class="form-control" ng-model="email" id="exampleInputEmail2" placeholder="Email address" required>
                    </div>
                    <div class="form-group col-md-6">
                        <label class="">Password</label>
                        <input type="password" class="form-control" id="exampleInputPassword2" …

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javascript node.js angularjs

Sat*_*dev

lucky-day

16
推荐指数

7
解决办法

6万
查看次数

在nodejs中向客户端发送响应

无法将响应数据发送回客户端.它的投掷错误说response.write()不是一个功能:

var express = require('express');
var app = express();
var request = require('request');

var port = process.env.PORT || 5000;
app.set('port', (port));

app.use(express.static(__dirname + '/'));
app.get('/', function(request, response) {
  response.render('/');
});

app.listen(app.get('port'), function() {
  console.log('Node app is running on port', app.get('port'));
});

app.post('/login', verifyLogin);

function verifyLogin(req, res, next) {
    var loginParams = {
        'username': req.body.username,
        'password': req.body.password
    };

    request({
        url: 'http://localhost:8084/xxx/auth', //URL to hit
        qs: {username: req.body.username, password: req.body.password},
        method: 'POST',
        json: {
            "username": req.body.username, "password": req.body.password
        }
        }, …

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javascript node.js

Sat*_*dev

lucky-day

4
推荐指数

2
解决办法

2万
查看次数

如何使用URIbuilder构建URI而不编码哈希

我有这样的URI:

java.net.URI location = UriBuilder.fromPath("../#/Login").queryParam("token", token).build();

我发送它作为回应: return Response.seeOther(location).build()

但是,在上面的URI中,#正在编码%23/.如何在不对哈希进行编码的情况下创建URI #.根据官方文件,fragment()必须使用一种方法来保持未编码.

URI的大多数组件都允许使用URI模板,但它们的值仅限于特定组件.例如

.UriBuilder.fromPath( "{ARG1}")建立( "富#栏"); 将导致'#'的编码,使得结果URI为"foo%23bar".要创建URI"foo #bar",请使用UriBuilder.fromPath("{arg1}").fragment("{arg2}").build("foo","bar").

从文档中查看示例,我不确定如何在我的案例中应用它.

最终的URI应如下所示:

http://localhost:7070/RTH_Sample14/#Login?token=eyJhbGciOiJSUzI1NiJ9.eyJpc3MiOiJodHRwczpcL1wvcnRoLmNvbSIsInN1YiI6IlJUSCIsInJvbGUiOiJVU0VSIiwiZXhwIjoxNDU2Mzk4MTk1LCJlbWFpbCI6Imtpcml0aS5rOTk5QGdtYWlsLmNvbSJ9.H3d-8sy1N-VwP5VvFl1q3nhltA-htPI4ilKXuuLhprxMfIx2AmZZqfVRUPR_tTovDEbD8Gd1alIXQBA-qxPBcxR9VHLsGmTIWUAbxbyrtHMzlU51nzuhb7-jXQUVIcL3OLu9Gcssr2oRq9jTHWV2YO7eRfPmHHmxzdERtgtp348

java rest jax-rs uribuilder

Sat*_*dev

2016 02-25

3
推荐指数

1
解决办法

7356
查看次数

如何在Nimbus JOSE + JWT中验证令牌签名

在使用Nimbus JOSE + JWT进行的每个资源请求中，我都有从服务器到客户端的来回令牌

用于创建JWT令牌的代码：

public class TokenProvider {

    String token = "";

    public String getToken(String email) {
        try {
            KeyPairGenerator keyGenerator = KeyPairGenerator.getInstance("RSA");
            keyGenerator.initialize(1024);

            KeyPair kp = keyGenerator.genKeyPair();
            RSAPublicKey publicKey = (RSAPublicKey) kp.getPublic();
            RSAPrivateKey privateKey = (RSAPrivateKey) kp.getPrivate();

            System.out.println("publicKey: " + publicKey);
            System.out.println("privateKey: " + privateKey.toString());

            JWSSigner signer = new RSASSASigner(privateKey);

            JWTClaimsSet claimsSet = new JWTClaimsSet();
            claimsSet.setSubject("RTH");
            claimsSet.setCustomClaim("email", email);
            claimsSet.setCustomClaim("role", "USER");
            claimsSet.setIssuer("https://rth.com");
            claimsSet.setExpirationTime(new Date(new Date().getTime() + 60 * 1000));

            SignedJWT signedJWT = new SignedJWT(new JWSHeader(JWSAlgorithm.RS256), claimsSet);

            signedJWT.sign(signer); …

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java oauth jwt

Sat*_*dev

2016 02-27

2
推荐指数

1
解决办法

7431
查看次数

使用spring框架连接到数据库时出错

我收到错误:

java.sql.SQLException: Invalid Oracle URL specified
at oracle.jdbc.driver.SQLStateMapping.newSQLException(SQLStateMapping.java:70)
    at oracle.jdbc.driver.DatabaseError.newSQLException(DatabaseError.java:133)
    at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:199)
    at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:263)
    at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:271)
    at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:445)
    at oracle.jdbc.driver.OracleDriver.connect(OracleDriver.java:428)
    at java.sql.DriverManager.getConnection(DriverManager.java:579)
    at java.sql.DriverManager.getConnection(DriverManager.java:190)
    at org.springframework.jdbc.datasource.DriverManagerDataSource.getConnectionFromDriverManager(DriverManagerDataSource.java:153)
    at org.springframework.jdbc.datasource.DriverManagerDataSource.getConnectionFromDriver(DriverManagerDataSource.java:144)
    at org.springframework.jdbc.datasource.AbstractDriverBasedDataSource.getConnectionFromDriver(AbstractDriverBasedDataSource.java:155)
    at org.springframework.jdbc.datasource.AbstractDriverBasedDataSource.getConnection(AbstractDriverBasedDataSource.java:120)
    at com.Templates.DBOperation.DBOperationBean.fetchName(DBOperationBean.java:34)
    at com.Templates.DBOperation.DBOperationClient.main(DBOperationClient.java:29)

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这是我的代码:

ApplicationContext.xml文件:

<beans>
 <bean id = "drds" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name = "driverClassName" value = "oracle.jdbc.driver.OracleDriver"/>
        <property name = "url" value = "jdbc:oracle:thin@localhost:1521:orcl"/>
        <property name = "username" value = "templates"/>
        <property name = "password" value = "templates"/>
    </bean>

    <bean id = "dob" class="com.Templates.DBOperation.DBOperationBean">
        <property name …

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java spring

Sat*_*dev

lucky-day

0
推荐指数

1
解决办法

329
查看次数