我想在python中向Selenium PhantomJS添加"自定义标题".这些是我想要添加的标题.
headers = { 'Accept':'*/*',
'Accept-Encoding':'gzip, deflate, sdch',
'Accept-Language':'en-US,en;q=0.8',
'Cache-Control':'max-age=0',
'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.116 Safari/537.36'
}
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这是我正在使用的代码:
from selenium import webdriver
service_args = [
'--proxy=127.0.0.1:9999',
'--proxy-type=socks5',
]
driver = webdriver.PhantomJS(service_args=service_args)
driver.set_window_size(1120, 550)
driver.get("https://duckduckgo.com/")
driver.find_element_by_id('search_form_input_homepage').send_keys("realpython")
driver.find_element_by_id("search_button_homepage").click()
print driver.current_url
driver.quit()
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如何修改包含这些自定义标头的代码?
请帮忙.
我正在构建一个需要用户位置的应用程序.我正在关注此处的Android培训文档,其中说:
shouldShowRequestPermissionRationale返回布尔值,指示我们是否应该显示具有请求权限的理由的UI(危险权限,ACCESS_FINE_LOCATION)
现在在这段代码中(取自文档本身):
if (ContextCompat.checkSelfPermission(thisActivity,
Manifest.permission.READ_CONTACTS)
!= PackageManager.PERMISSION_GRANTED) {
// Should we show an explanation?
if (ActivityCompat.shouldShowRequestPermissionRationale(thisActivity,
Manifest.permission.READ_CONTACTS)) {
// Show an explanation to the user *asynchronously* -- don't block
// this thread waiting for the user's response! After the user
// sees the explanation, try again to request the permission.
} else {
// No explanation needed, we can request the permission.
ActivityCompat.requestPermissions(thisActivity,
new String[]{Manifest.permission.READ_CONTACTS},
MY_PERMISSIONS_REQUEST_READ_CONTACTS);
// MY_PERMISSIONS_REQUEST_READ_CONTACTS is an
// app-defined int constant. The callback …Run Code Online (Sandbox Code Playgroud) 我正在尝试实现 staff_member_required 混合:
以下是我找到的两种方法:
第一的:
class StaffRequiredMixin(object):
@method_decorator(login_required)
def dispatch(self, request, *args, **kwargs):
if not request.user.is_staff:
messages.error(
request,
'You do not have the permission required to perform the '
'requested operation.')
return redirect(settings.LOGIN_URL)
return super(StaffRequiredMixin, self).dispatch(request,
*args, **kwargs)
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第二:
class StaffRequiredMixin(object):
@classmethod
def as_view(self, *args, **kwargs):
view = super(StaffRequiredMixin, self).as_view(*args, **kwargs)
return staff_member_required(view)
@method_decorator(login_required)
def dispatch(self, request, *args, **kwargs):
if not request.user.is_staff:
messages.error(
request,
'You do not have the permission required to perform the '
'requested operation.')
return redirect(settings.LOGIN_URL)
return …Run Code Online (Sandbox Code Playgroud)