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如何使用多个 yaml 文件生成 openAPI 代码

我有两个 yaml 文件,customer.yaml 和 employee.yaml。如何在单个项目中从这两个 yaml 文件生成 java 代码。我正在使用 gradle,我知道单个 yaml 的任务规范,但是如何指定多个 yaml。我应该在单个 openApiGenerator 下指定多个 inputSpec 吗?如果是,那么这样做的确切语法是什么。下面是我在 build.gradle 文件中的 openApiGenerator 任务。

``
openApiGenerate {
    generatorName = "spring"
    apiPackage = "com.xxx.generated.controller"
    modelPackage = "com.xxx.generated.model"
    inputSpec = "$rootDir//schema/employee.yaml".toString()
    outputDir = "$rootDir/generated".toString()
    configOptions = [
        dateLibrary: "java8"
    ]
    systemProperties = [
        invoker : "false", 
        generateSupportingFiles: "true"
    ]
    additionalProperties = [
        interfaceOnly : "true",
    ]
}
 ``
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我听说过 openApiGenerators 任务,它列出了通过 Open API Generators 可用的生成器,但找不到使用它的方法。

java gradle openapi swagger-codegen openapi-generator

7
推荐指数
2
解决办法
6900
查看次数

将对象转换为 JSON 字符串时发生 JsonMappingException - org.apache.avro.AvroRuntimeException:不是数组:

在将 Java 对象转换为 JSON 字符串时,我遇到了 JsonMappingException。以下是完整的异常消息。

com.fasterxml.jackson.databind.JsonMappingException: Not an array: {"type":"record","name":"ClearingSystemMemberIdentification2","namespace":"com.sam.eps.paymentdomain.avro.pacs002","doc":"Schema for com.sam.eps.iso.pacs002.ClearingSystemMemberIdentification2","fields":[{"name":"clearing_system_identification","type":["null",{"type":"record","name":"ClearingSystemIdentification2Choice","doc":"Schema for com.sam.eps.iso.pacs002.ClearingSystemIdentification2Choice","fields":[{"name":"code","type":["null",{"type":"string","avro.java.string":"String"}],"default":null},{"name":"proprietary","type":["null",{"type":"string","avro.java.string":"String"}],"default":null}]}],"default":null},{"name":"member_identification","type":["null",{"type":"string","avro.java.string":"String"}],"default":null}]} (through reference chain: com.sam.eps.paymentdomain.avro.pacs002.Document["fi_to_fi_payment_status_report"]->com.sam.eps.paymentdomain.avro.pacs002.FIToFIPaymentStatusReportV10["group_header"]->com.sam.eps.paymentdomain.avro.pacs002.GroupHeader91["instructed_agent"]->com.sam.eps.paymentdomain.avro.pacs002.BranchAndFinancialInstitutionIdentification6["financial_institution_identification"]->com.sam.eps.paymentdomain.avro.pacs002.FinancialInstitutionIdentification18["clearing_system_member_identification"]->com.sam.eps.paymentdomain.avro.pacs002.ClearingSystemMemberIdentification2["schema"]->org.apache.avro.Schema$RecordSchema["elementType"])
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下面是我用来将 Java 对象转换为 JSON 字符串的 java 代码。我尝试启用 ACCEPT_SINGLE_VALUE_AS_ARRAY、ACCEPT_EMPTY_ARRAY_AS_NULL_OBJECT 但仍然面临问题。不确定导致JsonMappingException 的原因:不是数组问题。

private String convertObjectToJson(Object request) throws JsonProcessingException {

        ObjectMapper objectMapper = new ObjectMapper();
        objectMapper.registerModule(new JavaTimeModule());
        SimpleModule simpleModule = new SimpleModule();
        simpleModule.addSerializer(OffsetDateTime.class, new JsonSerializer<OffsetDateTime>() {
            @Override
            public void serialize(OffsetDateTime offsetDateTime, JsonGenerator jsonGenerator, SerializerProvider serializerProvider) throws IOException {
                jsonGenerator.writeString(DateTimeFormatter.ISO_OFFSET_DATE_TIME.format(offsetDateTime));
            }
        });
        simpleModule.addSerializer(LocalDate.class, new JsonSerializer<LocalDate>() {
            @Override
            public void serialize(LocalDate localDate, JsonGenerator jsonGenerator, …
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java json jackson json-deserialization objectmapper

7
推荐指数
2
解决办法
1万
查看次数