我在drawable文件夹中有一个可绘制的形状.这是XML结构:
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<gradient
android:startColor="#4D0418"
android:centerColor="#5F031D"
android:endColor="#7D0227"
android:angle="-90" />
</shape>
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现在我想从运行时的java代码中更改startColor,centerColor,endColor.如何改变?
我正在使用SD卡,所以试图在运行时获得许可.这是代码:
public class MainActivity extends AppCompatActivity implements FileListFragment.OnFragmentInteractionListener {
private static final int MY_PERMISSIONS_REQUEST_READ_EXTERNAL_STORAGE = 111;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
if (ContextCompat.checkSelfPermission(this, Manifest.permission.READ_EXTERNAL_STORAGE) != PackageManager.PERMISSION_GRANTED) {
ActivityCompat.requestPermissions(this, new String[]{Manifest.permission.READ_EXTERNAL_STORAGE}, MY_PERMISSIONS_REQUEST_READ_EXTERNAL_STORAGE);
}
...................
................
}
@Override
public void onRequestPermissionsResult(int requestCode,
String permissions[], int[] grantResults) {
switch (requestCode) {
case MY_PERMISSIONS_REQUEST_READ_EXTERNAL_STORAGE: {
// If request is cancelled, the result arrays are empty.
if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
FileListFragment fileListFragment = FileListFragment.newInstance(0); // **Error line** …
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我的xml中有一个Listview.它的结构是这样的:
<ListView
android:id="@+id/SeriesCastListItemView"
android:paddingTop="10dip"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:divider="#FFFFFF"
android:dividerHeight="1px"/>
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现在我想为Listview
by java代码设置一个高度.我尝试使用以下代码.
ListView castListItemView = (ListView) findViewById(R.id.SeriesCastListItemView);
castListItemView.setAdapter(new CastAdapter(this, castDescriptionArr));
castListItemView.setLayoutParams(new ListView.LayoutParams(LayoutParams.FILL_PARENT, 500));
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但它给予了java.lang.ClassCastException: android.widget.AbsListView$LayoutParams
.我的代码有什么问题?
我正在使用Blackberry Facebook SDK(FacebookBlackBerrySDK-v0.8.25.jar)进行我的应用程序的Facebook集成.我使用以下代码.
ApplicationSettings as = new ApplicationSettings(NEXT_URL, APPLICATION_ID, APPLICATION_SECRET, PERMISSIONS);
Facebook fb = Facebook.getInstance(as);
User user = fb.getCurrentUser();
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它适用于OS 5.0和OS 6.0,但它不适用于OS 7.0.对于它,它正在提供"连接到Facebook"屏幕,而不是进一步.在调试屏幕中,我们得到以下信息:
2012-03-12 07:24:29 [INFO] BF-Navigate: https://www.facebook.com/dialog/oauth?scope=user_about_me,user_activities,user_birthday,user_education_history,user_events,user_groups,user_hometown,user_interests,user_likes,user_location,user_notes,user_online_presence,user_photo_video_tags,user_photos,user_relationships,user_relationship_details,user_religion_politics,user_status,user_videos,user_website,user_work_history,email,read_friendlists,read_insights,read_mailbox,read_requests,read_stream,xmpp_login,ads_management,user_checkins,friends_about_me,friends_activities,friends_birthday,friends_education_history,friends_events,friends_groups,friends_hometown,friends_interests,friends_likes,friends_location,friends_notes,friends_online_presence,friends_photo_video_tags,friends_photos,friends_relationships,friends_relationship_details,friends_religion_politics,friends_status,friends_videos,friends_website,friends_work_history,manage_friendlists,friends_checkins,publish_stream,create_event,rsvp_event,offline_access,publish_checkins,manage_pages&redirect_uri=http://www.facebook.com/connect/login_success.html&display=wap&client_id=XXXXXXXXXX&response_type=token
2012-03-12 07:24:29 [INFO] Access Token not found.
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可能是什么问题?
我有这样的布局.
<RelativeLayout
android:layout_width="fill_parent"
android:layout_height="fill_parent"
....>
<LinearLayout
android:id="@+id/box1"
android:layout_width="fill_parent"
android:layout_height="fill_parent">
...............
..............
</LinearLayout>
<LinearLayout
android:id="@+id/box2"
android:background="#c0000000"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >
.............
.............
</LinearLayout>
</RelativeLayout>
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Box2显示在Box1上方,由于Box2的半透明颜色,Box1部分可见.现在我想通过box2消耗掉所有的触摸事件,这样Box2中的Button
s和EditText
s就不起作用了.如何通过java代码完成?
我必须上课:
public class Product {
private int id;
private String title;
.............
.............
}
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其他类如下:
public class CatalogItem extends Product {
private int price;
private String[] colors;
.............
.............
}
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在布局中,我想访问子类和父类的所有属性。
<layout xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
xmlns:android="http://schemas.android.com/apk/res/android">
<data>
<variable
name="catalogItem "
type="com.appdemo.db.entity.CatalogItem" />
</data>
<TextView
android:id="@+id/productIdTextView"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginBottom="8dp"
android:layout_marginStart="8dp"
android:layout_marginTop="8dp"
android:text="@{((com.appdemo.db.entity.Product) catalogItem).id}"
app:layout_constraintBottom_toBottomOf="parent"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent" />
..................
..................
</layout>
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但是在数据绑定的情况下,却无法访问父类的属性。访问父类属性的正确方法是什么?
我使用KSOAP使用以下代码进行Web服务调用.
private static final String SOAP_ACTION = "http://www.tempuri.org/GetAuthenticateUser";
private static final String METHOD_NAME = "GetAuthenticateUser";
private static final String NAMESPACE = "http://www.tempuri.org/";
private static final String URL = "http://stage.mysite.com/FinancialSnapshotService/Service.asmx?WSDL";
// I have tried http://stage.mysite.com/FinancialSnapshotService/Service.asmx also
public void getResults() {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("vstrUserID", "vk@gmail.com");
request.addProperty("vstrPassword", "password");
SoapSerializationEnvelope soapEnvelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
soapEnvelope.dotNet = true;
soapEnvelope.setOutputSoapObject(request);
HttpTransportSE aht = new HttpTransportSE(URL);
try {
aht.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"UTF-8\"?>");
aht.call(SOAP_ACTION, soapEnvelope);
SoapObject result = (SoapObject) soapEnvelope.getResponse();
Log.d("WS", String.valueOf(result));
} catch …
Run Code Online (Sandbox Code Playgroud) 我在Eclipse的Blackberry Java Plug-in中创建了两个Blackberry项目,即MyProjectApp(设置为应用程序项目)和MyProjectLib(设置为Library项目).现在我创建了一个简单的MainScreen类,如下所示:
public class SampleScreen extends MainScreen {
public SampleScreen (){
RichTextField topbar = new RichTextField("hello world");
add(topbar);
}
}
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现在我将MyProjectLib导出为Jar文件,并在MyProjectApp中添加相同的外部Jar.现在我要使用以下方法触发SampleScreen:
public class MyProjectMain extends UiApplication{
public static void main(String[] args) {
MyProjectMain theApp = new MyProjectMain();
theApp.enterEventDispatcher();
}
public LangHostMain(){
// Push a screen onto the UI stack for rendering.
pushScreen(new SampleScreen());
}
}
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它给出了以下错误:
模块"MyProjectApp"存在验证错误.启动MyProjectApp时出错:模块"MyProjectApp"出现验证错误.
但是,如果我将SampleScreen类移动到MyProjectApp,它工作正常.导出Jar并使用它有什么问题?需要什么类型的验证?
我必须在ImageView上显示一个动画.它会像卡片翻转一样.显示X图像的ImageView将翻转并显示Y图像.我怎么能这样做?任何的想法?
我想实现一个像下面这样有一个文本框和多个图标的 Appbar:
图标可以很容易地添加到操作中,但如何添加文本框并向其添加搜索操作。有很多搜索栏插件可用,但都占据了整个应用栏,没办法提提示。任何人都可以提供一些想法,这对我有很大帮助。
android ×7
blackberry ×2
animation ×1
appbar ×1
colors ×1
data-binding ×1
facebook ×1
flip ×1
flutter ×1
gradient ×1
imageview ×1
jar ×1
ksoap2 ×1
layout ×1
layoutparams ×1
listview ×1
parent-child ×1
permissions ×1
search ×1
shape ×1
touch ×1
verification ×1
web-services ×1