我正在尝试使用Spring/JPA配置和Maven多模块项目.这是总体布局.我有一个带有5个子模块的根模块.
backoffice (root maven module) | -(maven module)-----core (this is where persistence.xml and entityManager stuff resides). | -(maven module)-----employee (employee related entities, controllers, etc.) | -(maven module)-----vendor (vendor related entities, controllers, etc.) | -(maven module)-----customer (customer related entities, controllers, etc.) | -(maven module)-----web (contains all the web stuff).
我在core/src/main/resources/META-INF(persistence.xml,spring-context w/EntityManagerFactory,dataSource等)中拥有所有jpa内容.我的想法是希望在所有子模块(员工,供应商和客户)之间共享持久性内容.
问题是,当Web应用程序启动时,它找不到EntityMangerFactory.如果我在每个子模块(员工,供应商和客户)中设置JPA东西,那么它可以工作.
如何在核心中设置所有与持久性相关的东西,然后在其他模块中共享它？
提前致谢.
我正在使用Scala match/case语句来匹配给定java类的接口.我希望能够检查一个类是否实现了接口的组合.我似乎能够使这个工作的唯一方法是使用match/case看似丑陋的嵌套语句.
假设我有一个实现Person,Manager和Investor的PersonImpl对象.我想看看PersonImpl是否实现了Manager和Investor.我应该能够做到以下几点:
person match {
case person: (Manager, Investor) =>
// do something, the person is both a manager and an investor
case person: Manager =>
// do something, the person is only a manager
case person: Investor =>
// do something, the person is only an investor
case _ =>
// person is neither, error out.
}
这case person: (Manager, Investor)是行不通的.为了使它工作,我必须做以下似乎很难看.
person match {
case person: Manager = {
person match {
case …