什么是打破子程序并继续处理脚本其余部分的最佳方法？
即
#!/usr/bin/perl
use strict;
use warnings;
&mySub;
print "we executed the sub partway through & continued w/ the rest
of the script...yipee!\n";
sub mySub{
print "entered sub\n";
#### Options
#exit; # will kill the script...we don't want to use exit
#next; # perldoc says not to use this to breakout of a sub
#last; # perldoc says not to use this to breakout of a sub
#any other options????
print "we should NOT see this\n";
}
我的表格中有一个全文字段.其中一行是:
"this is the dog that ran over there"
我有以下mysql语句:
SELECT *
FROM `table`
WHERE MATCH (column) AGAINST ('dog that ran')
...返回0条记录
SELECT *
FROM `table`
WHERE `column` LIKE '%dog that ran%'
...返回1条记录
为什么不同？他们应该都返回1条记录,对吗？
如何在仍能访问该密码的同时将用户密码安全地存储在cookie中？我有一个cookie存储密码的用户名和sha1版本但是当我尝试检索它们时,我得到(如预期的)用户名和密码的sha1版本,而不是密码本身.谢谢!
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title></title>
</head>
<body>
<form id='my_login' name='my_login' action='<?php htmlentities($_SERVER['PHP_SELF'])?>' method='post' accept-charset='UTF-8'>
<input type='hidden' name='submitted' id='submitted' value='1'/>
<label for='username'>Username: </label>
<input id='username' type='text' name='username' value='<?php if(isset($_COOKIE['username'])) echo htmlentities($_COOKIE['username']); ?>'/>
<br/>
<label for='username'>Password: </label>
<input id='password' type='password' name='password' value='<?php if(isset($_COOKIE['password'])) echo htmlentities($_COOKIE['password']); ?>'/>
<br/>
<label for "set_cookie">Remember Me</label>
<input type="checkbox" name="set_cookie" id="set_cookie" value="1"/>
<button id='submit' type='submit' name='submit'>login</button>
</form>
</body>
<html>
我经常旅行,但住在纽约,我正试图显示纽约时间,无论我在哪里.我怎么用Python做到这一点？我有以下,这不起作用,给我错误:
`'module' object is not callable`
此外,我不确定下面的方法是否会在夏令时之间正确更新:
import pytz
utc = pytz.utc
utc_dt = datetime(2002, 10, 27, 6, 0, 0, tzinfo=utc)
eastern = pytz.timezone('US/Eastern')
loc_dt = utc_dt.astimezone(eastern)
fmt = '%Y-%m-%d %H:%M:%S %Z%z'
loc_dt.strftime(fmt)
newb to python和pyramid/pylons.用户登录后,我想在我的数据库中获取一些数据并将其存储在会话变量中.我已经能够用remember()存储用户的登录ID.使用request.session,我可以设置一个会话变量,只要它是一个字符串,但如果我尝试从我的数据库中检索一些东西,我会收到一个错误:"BadPickleGet: ".这是我的观点的相关部分:
if 'form.submitted' in request.params:
login = request.params['login']
password = request.params['password']
if User.check_password(login, password):
headers = remember(request, login) # ie dave
session = request.session
#session['myvar'] = 'somethinghardcoded' # this works!
session['myvar'] = User.myfield # this doesn't work!
session.save()
return HTTPFound(location=came_from, headers=headers)
作为python的新手,我不太清楚为什么我会得到不一致的结果.我注册了一个用户,我的表中的密码最终成为哈希版本.当用户更新其密码时,表中的密码最终为未散列的版本.显然,我想要哈希版本.我究竟做错了什么？(如果重要的话,我正在使用SQLAlchemy和mysql.)
我有以下内容:
def hash_password(password):
blah, blah, blah # hash my password here
return hashed_password
class User(Base):
__tablename__ = 'mytable'
email = Column('email')
_password = Column('password')
def _get_password(self):
return self._password
def _set_password(self, password):
self._password = hash_password(password)
password = property(_get_password, _set_password)
password = synonym('_password', descriptor=password)
def __init__(self, password="", email=""):
self.email = email
self.password = password
@classmethod
def register(cls, email, password):
return DBSession.add(User(email=email,password=password)) # this correctly hashes the password
@classmethod
def update(cls, email, password):
return DBSession.query(cls).filter(cls.email == email).update({'password': password}) #password ends up being …我有一个HTML输入和一个字体真棒图标.我不想限制用户输入的文本量.相反,我想这样做,以便文本不重叠.fa-comment-o ...任何额外的文本将被隐藏(不是截止,只是隐藏).我可以给出的最好的例子是当你在谷歌中输入一些东西时,文本不会与麦克风重叠,如果关闭它们也不会切割(它们使用图像而我使用的是字体图标).
<div id="container">
<input id="input" value="This is some really long text that will almost certainly not fit within the text box. What I'd like to do is not bleed beyond the comment icon."/>
<i class="fa fa-comment-o"></i>
</div>
#input{
width: 300px;
height: 25px;
margin-right: -30px;
}
.fa-comment-o{
font-size: 16px;
color: #333;
cursor: pointer;
right: 10px;
}
我有一个在 Docker 5000 端口上运行的应用程序。我试图通过 Docker compose 在 nginx 中运行反向代理，但无法与主机的端口 5000 通信。在我的 docker-compose.yml 文件中，我有：
ports:
- 80:80
- 443:443
- 5000:5000
当我尝试运行它时，我得到：
ERROR: for nginx Cannot start service nginx: driver failed programming external connectivity on endpoint nginx (374026a0d34c8b6b789dcd82d6aee6c4684b3201258cfbd3fb18623c4101): Error starting userland proxy: listen tcp 0.0.0.0:5000: bind: address already in use
如果我注释掉，- 5000:5000我会得到：
[error] 6#6: *1 connect() failed (111: Connection refused) while connecting to upstream
如何从 Docker nginx 容器连接到主机中已经运行的应用程序？
编辑：
我的 nginx.conf 文件
user www-data;
worker_processes auto;
pid /run/nginx.pid;
events …