小编smi*_*hyy的帖子

当我按完iOS时,textview键盘不会辞职

我有一个textview,当我按完后textview开始一个新的行.

我已经实现了这些方法并添加了所有委托

@property (nonatomic, strong) IBOutlet UITextView *textField;

-(void)textViewDidEndEditing:(UITextView *)textView //was UITextField
{
    [self.textField resignFirstResponder];
}

- (BOOL)textFieldShouldReturn:(UITextView *)textField{

    [textField resignFirstResponder];
    return YES;

}
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我将键盘返回键设置为在属性检查器中完成.我希望键盘上的完成键可以让第一响应者辞职,但它似乎不起作用.

- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {

    if([text isEqualToString:@"\n"]) {
        [textView resignFirstResponder];
        return NO;
    }
    return YES;

    // error thrown here saying code will never execute
    if(range.length + range.location > textField.text.length)
{
    return NO;
}

NSUInteger newLength = [textField.text length] + [string length] - range.length;
return newLength <= 300;
}
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我如何添加这两个语句,以便它们可以正常工作而不会出错?

objective-c uitextview uikeyboard ios resignfirstresponder

5
推荐指数
1
解决办法
949
查看次数

如何限制UITextView iOS中的字符

我有一个UITextView,我想限制用户可以输入的字符数.如果文本字段为空但我没有运气,我也试图显示警告.

textview.h

@property (nonatomic,strong) IBOutlet UITextView *textField;
@property (nonatomic, retain) NSString *userText;

textview.m

- (IBAction)next:(id)sender {

    self.userText = self.textField.text;

    if ([self.textField.text length] == 0) {
            UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Error!"
                                                                message:@"Enter some text"
                                                               delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
            [alertView show];
        }
}
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这是文本限制方法似乎不起作用,

- (BOOL)textView:(UITextView *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string{

    if(range.length + range.location > textField.text.length)
    {
        return NO;

    } else {

    NSUInteger newLength = [textField.text length] + [string length] - range.length;
    return newLength <= 70;
    return (textField.text.length <= 70);
}
}
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objective-c nsstring uitextview nsinteger ios

3
推荐指数
1
解决办法
8062
查看次数

将微调器数组中的选定值传递给另一个Android类

我正在建立一个具有自毁图像的应用程序,我试图将从微调框中选择的值传递给另一个类

final String titles[] = {"1 Second","2 Seconds", "3 Seconds","4 Seconds","5 Seconds","6 Seconds","7 Seconds", "8 seconds, "9 seconds", 10 seconds};
    mSeconds = (Spinner) view.findViewById(R.id.secondsSpinner);
    ArrayAdapter<String> arrayAdapter = new ArrayAdapter<String>(getActivity(), android.R.layout.simple_spinner_item, titles);
    arrayAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);

mSeconds.setAdapter(arrayAdapter);
mSeconds.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
    @Override
    public void onItemSelected(AdapterView<?> parentView, View selectedItemView, int position, long id) {
        int secondsToUse = position + 1;
    }

    @Override
    public void onNothingSelected(AdapterView<?> parentView) {
        // do nothing
    }

});
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我的意图方法:

Intent recipientsIntent = new Intent(getActivity(), RecipientsActivity.class);
 recipientsIntent.putExtra("key1", titles);
                      startActivity(recipientsIntent);
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如何将选中的值传递给另一个类?我的方法传递整个数组而不是选中的项目.

java arrays android spinner android-intent

1
推荐指数
1
解决办法
1498
查看次数

在textview Android中显示秒数倒计时

我有一个定时器,有一个秒数从一直到0倒数,所以如果我把5个textview标签,我希望它显示5,4,3,2,1,0,我已经有了计时器停止.我传入用户选择的随机数,所以我将变量S传递给计时器

我的观点:

 mSeconds = (TextView)findViewById(R.id.secondsLabel);
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我的计时器:

int s = //int taken from on spinner in another class

Timer timer = new Timer();
        timer.schedule(new TimerTask() {
            @Override
            public void run() {
                finish();
            }
        }, s * 1000);
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所以当我把mSeconds.setText(//what should i add here);数字显示为0时

java int android textview countdowntimer

1
推荐指数
1
解决办法
1184
查看次数