我想将IOCTL命令发送到连接到我的计算机的PC/SC阅读器(win7 64位).为了发送IOCTL命令,我需要一个HANDLE到设备,我无法创建.
设备在设备管理器中列为"OMNIKEY 1021",物理设备对象名称为"\ Device\USBPDO-15".使用"WinObj"工具,我可以检测到2个符号链接:USB#VID_076B&PID_1021#5&291f6990&0&1#{50dd5230-ba8a-11d1-bf5d-0000f805f530} USB#VID_076B&PID_1021#5&291f6990&0&1#{a5dcbf10-6530-11d2-901f-00c04fb951ed}
我的问题:我无法使用CreateFile函数为此设备创建有效句柄:
我发现MSDN/Google上有几种可能的格式用作CreateFile函数的lpFileName参数,但它们似乎都不起作用:
\\?\Device\USBPDO-15
\\.\Device\USBPDO-15
\\GLOBAL??\Device\USBPDO-15
\GLOBAL??\Device\USBPDO-15
\\.\USBPDO-15
\\?\USB#VID_076B&PID_1021#5&291f6990&0&1#{50dd5230-ba8a-11d1-bf5d-0000f805f530}
\\.\USB#VID_076B&PID_1021#5&291f6990&0&1#{50dd5230-ba8a-11d1-bf5d-0000f805f530}
\\GLOBAL??\USB#VID_076B&PID_1021#5&291f6990&0&1#{50dd5230-ba8a-11d1-bf5d-0000f805f530}
\GLOBAL??\USB#VID_076B&PID_1021#5&291f6990&0&1#{50dd5230-ba8a-11d1-bf5d-0000f805f530}
\\?\USB#VID_076B&PID_1021#5&291f6990&0&1#{a5dcbf10-6530-11d2-901f-00c04fb951ed}
\\.\USB#VID_076B&PID_1021#5&291f6990&0&1#{a5dcbf10-6530-11d2-901f-00c04fb951ed}
\\GLOBAL??\USB#VID_076B&PID_1021#5&291f6990&0&1#{a5dcbf10-6530-11d2-901f-00c04fb951ed}
\GLOBAL??\USB#VID_076B&PID_1021#5&291f6990&0&1#{a5dcbf10-6530-11d2-901f-00c04fb951ed}
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代码示例:
#include <iostream>
#include <Windows.h>
int main (int argc, char* argv[])
{
HANDLE handle = CreateFile (
L"\\\\.\\Device\\USBPDO-15",
0,
FILE_SHARE_READ, //FILE_SHARE_WRITE,
NULL,
OPEN_EXISTING,
0, //FILE_FLAG_OVERLAPPED,
NULL
);
if (handle == INVALID_HANDLE_VALUE)
std::cout << "INVALID HANDLE" << std::endl;
else
std::cout << "HANDLE: " << std::hex << handle << std::endl;
}
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笔记:
编辑:
解: