小编spi*_*er8的帖子

我一直认为to_date函数字符串和日期格式应该匹配.为什么以下声明工作正常？

select TO_DATE('20151014','yyyy-mm-dd') from dual; 

oracle现在在将字符串转换为日期之前忽略了特殊字符吗？

这是在Oracle 11g中.

我试图在case语句中进行聚合.我发现了两种方法.谁能说两者之间的区别是什么？

1. (CASE WHEN Event = 5 THEN count(*) ELSE 0 END ) Follow_Count GROUP BY Event;

2. SUM(CASE Event WHEN 5 THEN 1 ELSE 0 END) AS Follow_Count

我试图从all_tab_partitions表中获取当前分区的名称.当我尝试比较high_value(长数据类型)和数字.它抛出一个错误:

ORA-00997:非法使用LONG数据类型

SELECT PARTITION_NAME, HIGH_VALUE FROM ALL_TAB_PARTITIONS
WHERE TABLE_OWNER='SCHEMA_NAM'
AND TABLE_NAME='TABLE_NAME'
AND HIGH_VALUE>to_number(TO_CHAR(TRUNC(ADD_MONTHS(SYSDATE, 1), 'MONTH'), 'YYYYDDD'))
/

我正在阅读数据库中的电子邮件.我希望将电子邮件作为超链接回应,但它不起作用.

<?php
$un = $_POST['username'];
$pw = $_POST['password'];

// connect to the db
$user = 'proc';
$pswd = 'passwd';
$db = 'school';
$conn = mysql_connect('localhost', $user, $pswd);
mysql_select_db($db, $conn);

// run the query to search for the username and password the match
$query = "SELECT email AS text FROM contact";
$result = mysql_query($query) or die("Unable to verify user because : " . mysql_error());

// this is where the actual verification happens
while ($row = mysql_fetch_assoc($result)) {
    echo ("\n".$row['text']);
    echo "<a …