我有这样一张桌子:
CREATE TABLE `products` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(512) NOT NULL,
`description` text,
PRIMARY KEY (`id`),
) ENGINE=InnoDB AUTO_INCREMENT=38 DEFAULT CHARSET=utf8;
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和这样的一个:
CREATE TABLE `product_variants` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`product_id` int(11) unsigned NOT NULL,
`product_code` varchar(255) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `product_code` (`product_code`),
KEY `product_variant_product_fk` (`product_id`),
CONSTRAINT `product_variant_product_fk` FOREIGN KEY (`product_id`) REFERENCES `products` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=1037 DEFAULT CHARSET=utf8;
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和这样的SQL语句
SELECT p.id AS id, p.name AS name, p.description AS description, pv.id …Run Code Online (Sandbox Code Playgroud) 我已经启动了一个Compojure(Jetty)服务器:
(defonce *server* (run-server {:host "localhost" :port 8080} "/*" (servlet routes)))
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但是netstat仍然显示它正在监听0.0.0.0:8080,即所有IP.
传递给run-server以使其在单个IP上侦听的正确参数是什么?
如何在Java中使用COM在Windows中创建播放列表(在Windows上,即没有AppleScript)?
我在这里找到了一个库,可以完成我需要的大部分工作,并且我在ITPlaylist.java中添加了一些代码,在iTunes对象ITPlaylist上调用"AddTrack"方法(在文档中提到):
public void addTrack(ITTrack track) {
ITPlaylistKind k = getKind();
if (k == ITPlaylistKindUser) {
Dispatch.put(object, "AddTrack", track);
} else
throw new UnsupportedOperationException("can only add track to user playlists - kind : " + k);
}
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但是我收到一个错误:
# A fatal error has been detected by the Java Runtime Environment:
#
# EXCEPTION_ACCESS_VIOLATION (0xc0000005) at pc=0x1000e150, pid=3184, tid=3896
#
# JRE version: 6.0_15-b03
# Java VM: Java HotSpot(TM) Client VM (14.1-b02 mixed mode, sharing …Run Code Online (Sandbox Code Playgroud)