小编jah*_*hra的帖子

实体管理器 Find() 方法的正确使用

我在使用 EntityManager Here my User 实体从数据库中获取数据时遇到问题

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@JsonProperty
private Integer id;
@Column(name = "username", length = 20, nullable = false)
@JsonProperty
private String username;
@Column(name = "password", nullable = false, unique = true)
@JsonProperty
private String password;
@Column(name = "enabled", nullable = false)
@JsonProperty
private boolean enabled;
@Column(name = "email", nullable = false, unique = true)
@JsonProperty
private String email;
@OneToMany(mappedBy = "user", cascade = {CascadeType.ALL}, fetch = FetchType.LAZY)
private Set<UserRole> userRoles;
//getters and setters
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我尝试使用用户名搜索用户:

public …
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hibernate entitymanager

4
推荐指数
1
解决办法
6343
查看次数

休眠:createQuery在没有活动事务的情况下无效

我的Spring + Hibernate项目遇到一些问题。当我尝试获取数据时,我有:

HTTP状态500-请求处理失败;嵌套的异常是org.hibernate.HibernateException:如果没有活动的事务,createQuery无效。这是我的xml配置代码:

<beans xmlns="http://www.springframework.org/schema/beans"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"    xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx.xsd">

<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
            destroy-method="close">
    <property name="driverClassName" value="com.mysql.jdbc.Driver" />
    <property name="url" value="jdbc:mysql://localhost:3306/users" />
    <property name="username" value="root"/>
    <property name="password" value="12345"/>
</bean>

<bean id="SessionFactory"
               class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="dataSource" />
    <property name="annotatedClasses">
        <list>
            <value>com.springapp.model.User</value>
            <value>com.springapp.model.UserRole</value>
            <value>com.springapp.model.Project</value>
        </list>
    </property>
    <property name="hibernateProperties">
        <props>
            <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
            <prop key="hibernate.show_sql">false</prop>
            <prop key="hibernate.current_session_context_class">thread</prop>
        </props>
    </property>
</bean>

<tx:annotation-driven transaction-manager="transactionManager"/>

<bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
    <property name="sessionFactory" ref="SessionFactory"/>
</bean>
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DAO的方法

@Override
public List<User> showAllUsers(){
    List<User> users = new ArrayList<User>();
    Session session = …
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java spring hibernate spring-mvc

3
推荐指数
1
解决办法
1万
查看次数

Liferay Portlet响应:如何设置状态代码?

我有一个简单的方法接受我的liferay portlet中的PortletResponse和PortletRequest

public void remove(PortletResponse response, PortletRequest request) {

}
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我想将响应状态设置为404,就像我可以用HttpServletResponse做的那样 httpResponse.sendError(HttpServletResponse.SC_BAD_REQUEST)

你能告诉我怎么做吗?

portlet liferay

3
推荐指数
1
解决办法
3643
查看次数

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hibernate ×2

entitymanager ×1

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