我一直收到错误:
The file "Blah" couldn't be opened because you do not have permission to view it.
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我在这个问题上尝试了前5个答案 -
"无法打开文件"MyApp.app",因为在Xcode 6 Beta 4中运行应用程序时,您无权查看它
但它们不起作用.
注:我删除了debug,并release从Test 在Build Settings与所得到的数据多次被清除.
info.plist中
说明:我有一个包含NavigationBar和UIWebView的viewcontroller.webview在.m文件中设置为全屏.在视图控制器上,导航栏布置在前面.
会发生什么:当我运行应用程序时,唯一可见的是webview(全屏),但导航栏不在那里.
假设发生了什么:这是不言自明的,但导航栏假设在其下面是webview的顶部.
它看起来像什么
.m文件
#import "SecondViewController.h"
@interface ViewController2 ()
@end
@implementation ViewController2
- (void)viewDidLoad
{
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
UIWebView *webview2=[[UIWebView alloc]initWithFrame:CGRectMake(0, 0, self.view.frame.size.width,self.view.frame.size.height)];
NSString *url2=@"http://bithumor.co/server/trending/index1.php";
NSURL *nsurl2=[NSURL URLWithString:url2];
NSURLRequest *nsrequest2=[NSURLRequest requestWithURL:nsurl2];
[webview2 loadRequest:nsrequest2];
webview2.scrollView.bounces = NO;
[self.view addSubview:webview2];
@end
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.h文件
#import <UIKit/UIKit.h>
@interface ViewController2 : UIViewController
@end
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问题/问题:导航栏不可见,如何解决这个问题,以便webview和导航栏都可见?
我刚刚将我的xcode8更新为Swift 3并收到此错误:
Value of type 'DispatchQueue' has no member 'asynchronously'
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在这条线上:
DispatchQueue.main.asynchronously(execute:
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这是整个代码段:
DispatchQueue.main.asynchronously(execute: {
//Display alert message with confirmation
let myAlert = UIAlertController(title: "Alert", message:messageToDisplay, preferredStyle: UIAlertControllerStyle.Alert);
let okAction = UIAlertAction(title:"OK", style:UIAlertActionStyle.Default){
action in self.dismissViewControllerAnimated(true, completion:nil);
}
myAlert.addAction(okAction)
self.presentViewController(myAlert, animated:true, completion:nil);
});
}
}
catch let error as NSError {
print(error.localizedDescription)
}
}
task.resume()
}
}
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最近更新到Swift 3给了我很多错误,它们会自动修复,但是这个不会自行解决,我不知道该怎么办.
我不断收到错误:
致命错误:在第42行中,不能在表达式的结果上使用isset()(可以改用“ null!== expression”)
这是第42行:
if (isset($_GET['reply_id'] && $_GET['reply_user'])) {
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这是该代码的“整个”部分:
<?php
if (isset($_GET['reply_id'] && $_GET['reply_user'])) {
$reply_id = $_GET['reply_id'];
$reply_user = $_GET['reply_user'];
echo '<form action="#" method="post">
<center>
<textarea rows="4" cols="50" maxlength="300" name="comment_box" placeholder="Say something awesome..." Style="width:94%;font-family:helvetica;font-size:14px;">@' . $reply_user . '.</textarea></center>
<center><input type="submit" name="post2" class="post_text" value="Post"></center>
</form>';
}
?>
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我该如何解决?