我正在我的项目中使用 Spring Boot、GraphQL 和 gRPC。我一直在通过运行它来测试该应用程序,它一直运行良好。但是,当我尝试使用mvn package生成 gRPC 类来构建它时,它给了我一堆错误,如下所示:
2018-10-24 16:14:30.454 INFO 67640 --- [ main] s.w.s.m.m.a.RequestMappingHandlerMapping : Mapped "{[/graphiql]}" onto public void com.oembedler.moon.graphiql.boot.GraphiQLController.graphiql(javax.servlet.http.HttpServletResponse) throws java.io.IOException
2018-10-24 16:14:30.492 INFO 67640 --- [ main] o.s.w.s.handler.SimpleUrlHandlerMapping : Mapped URL path [/webjars/**] onto handler of type [class org.springframework.web.servlet.resource.ResourceHttpRequestHandler]
2018-10-24 16:14:30.492 INFO 67640 --- [ main] o.s.w.s.handler.SimpleUrlHandlerMapping : Mapped URL path [/**] onto handler of type [class org.springframework.web.servlet.resource.ResourceHttpRequestHandler]
2018-10-24 16:14:30.537 INFO 67640 --- [ main] o.s.w.s.handler.SimpleUrlHandlerMapping : Mapped URL path [/**/favicon.ico] onto handler …Run Code Online (Sandbox Code Playgroud)我为 python 安装了 rtmidi 并且能够导入它。但是,当我尝试运行此处给出的整个用法示例时:https : //pypi.python.org/pypi/python-rtmidi,出现此错误:
AttributeError: 'rtmidi_python.MidiOut' 对象没有属性 'get_ports'
这是完整的代码:
import time
import rtmidi_python as rtmidi
midiout = rtmidi.MidiOut()
available_ports = midiout.get_ports()
if available_ports:
midiout.open_port(0)
else:
midiout.open_virtual_port("My virtual output")
note_on = [0x90, 60, 112] # channel 1, middle C, velocity 112
note_off = [0x80, 60, 0]
midiout.send_message(note_on)
time.sleep(0.5)
midiout.send_message(note_off)
del midiout
Run Code Online (Sandbox Code Playgroud)
我在导入部分稍微修改了代码,因为不知何故,当我放入时它不起作用,import rtmidi但当我放入import rtmidi_python.
我正在使用 Python 3.5。任何帮助将不胜感激,谢谢!
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