我试图构建和编译我的程序时遇到此错误.现在我无法打开程序中的所有.cpp文件.
make [2]:*没有规则来制作目标
Checker.cpp', needed by构建/调试/ GNU-Linux-x86/Checker.o'.停止.
有人可以帮我这个吗？我检查了所有在线资源,但我似乎无法找到解决方案.我迫切需要这个解决.感谢给予的任何帮助.
I have a problem regarding my intent. It seems that my app crashes when i select the intent. I found the line of error code due to the stack trace. But i couldn't find anything wrong with it. Hope anyone can help me with this.
This is the java code in line 121:
startActivity(new Intent(Intent.ACTION_INSERT, getIntent().getData()));
This is the stack trace:
11-24 16:09:24.634: ERROR/AndroidRuntime(222): Uncaught handler: thread main exiting due to uncaught exception
11-24 16:09:24.834: ERROR/AndroidRuntime(222): android.content.ActivityNotFoundException: No Activity found …我正在尝试创建一个while循环,当满足字符串条件或计时器条件时,程序将跳出循环并打印出所需的输出.当打印出所需的输出时,输出将包含比较答案之前和之后的时间差.
但是循环并没有像我期望的那样运行.所以任何人都可以帮我弄清楚这段代码的问题在哪里？
以下是我的代码:
void startGame(time_t cd,int gl){
string guessWord;
time_t start, end, diff,timeLeft;
cout << "Scrambled word is " << randomizeWord(gl) << endl;
while (timeLeft != cd || guessWord.compare(originalWord) == 0)
{
start = time(0);
cout << "You have " << cd << " seconds to guess." << endl;
cout << "Enter guess : ";
cin >> guessWord;
end = time(0);
diff = end - start;
//total_time = total_time + diff;
timeLeft = cd - diff;
if(guessWord.compare(originalWord) != 0)
{ …我正在尝试使用迭代器擦除向量中的最后一个元素.但是在擦除元素时我遇到了分段错误.
以下是我的代码:
for (vector<AccDetails>::iterator itr = accDetails.begin(); itr != accDetails.end(); ++itr) {
if (username == itr->username) {
itr = accDetails.erase(itr);
}
}
我的迭代有问题吗？
我被赋予这个算法来编写一个哈希函数:
BEGIN Hash(string)
UNSIGNED INTEGER key = 0;
FOR_EACH字符IN字符串
键=((键<< 5)+键)^字符;
END FOR_EACH
RETURN键;
结束哈希
的<<操作者参照位左移.在^指异或运算和性质是指该字符的ASCII值.看起来非常简单.
以下是我的代码
unsigned int key = 0;
for (int i = 0; i < data.length(); i++) {
key = ((key<<5) + key) ^ (int)data[i];
}
return key;
但是,当我实际上从0开始得到一个哈希值时,我一直变得荒谬的正面和负面的巨大数字n.n是用户事先设定的值.我不确定哪里出了问题,但我认为这可能是XOR操作.
任何建议或意见将不胜感激.谢谢!
我目前正在尝试在一种方法中插入数据，然后将其添加到向量中。由于某种原因，当我到达输入第二组x y的点时，总是会遇到分割错误。
我认为这是导致故障的部分：
if (shape == "square") {
for (int i = 0; i < 4; i++) {
cout << "Please enter x-coordinate of pt." << i+1 << " : ";
cin >> x;
cout << "Please enter y-coordinate of pt." << i+1 << " : ";
cin >> y;
sq->setName(shape);
sq->setContainsWarpSpace(type);
sq->setVertices(i,x,y);
shapes.push_back(sq);
}
}
该setName和setContainsWarpSpace是正常的设置方法。
编辑
好吧，我刚刚找到了导致分段错误的行。这是我的setName方法
void ShapeTwoD::setName(string name) {
this->name = name;
}
EDIT2
根据要求，这是名称和形状的定义。是的，sq是Square类的指针。
内部驱动程序类：
string shape; …这是我提出的上一个问题的延续.从我的Server.class NullPointerException调用public static void main方法时,我似乎得到了.
这是我的Server.class
public static void main(String[] args) throws IOException {
try {
//what happens here is that I open up a socket and start listening
}
catch (Exception X) {System.out.println(X);}
}
这是我在另一个类中的runServer方法:
public static void runServer() throws Exception{
File sourceFile = new File("/Users/Joel/NetbeansProjects/FYP/src/ui_v2/Server.java");
JavaCompiler compiler = ToolProvider.getSystemJavaCompiler();
StandardJavaFileManager fileMgr = compiler.getStandardFileManager(null, null, null);
fileMgr.setLocation(StandardLocation.CLASS_OUTPUT, Arrays.asList(new File("/Users/Joel/NetbeansProjects/FYP/src/ui_v2")));
compiler.getTask(null, fileMgr, null, null, null,
fileMgr.getJavaFileObjectsFromFiles(Arrays.asList(sourceFile)));
fileMgr.close();
try {
Class params[] = {};
Object paramsObj[] = {}; …