小编Jus*_*ill的帖子

使用jq指望多个级别

我们发现了一些与感染有关的域名.现在我们在.json文件中有一个DNS名称列表,我想生成一个汇总输出,显示:用户列表,他们访问的唯一域,总计数.如果我也可以计算每个域名的奖励积分.

以下是该文件的示例:

{"machine": "possible_victim01", "domain": "evil.com", "timestamp":1435071870}
{"machine": "possible_victim01", "domain": "evil.com", "timestamp":1435071875}
{"machine": "possible_victim01", "domain": "soevil.com", "timestamp":1435071877}
{"machine": "possible_victim02", "domain": "bad.com", "timestamp":1435071877}
{"machine": "possible_victim03", "domain": "soevil.com", "timestamp":1435071879}
Run Code Online (Sandbox Code Playgroud)

理想情况下,我希望输出类似于:

{"possible_victim01": "total": 3, {"evil.com": 2, "soevil.com": 1}}
{"possible_victim02": "total": 1, {"bad.com": 1}}
{"possible_victim03": "total": 1, {"soevil.com": 1}}
Run Code Online (Sandbox Code Playgroud)

我很乐意接受:

{"possible_victim01": "total": 3, ["evil.com", "soevil.com"]}
{"possible_victim02": "total": 1, ["bad.com"]}
{"possible_victim03": "total": 1, ["soevil.com"]}
Run Code Online (Sandbox Code Playgroud)

我可以获得每个用户的总记录数,但是我丢失了域名列表:

cat sample.json | jq -s 'group_by(.machine) | map({machine:.[0].machine,domain:.[0].domain, count:length}) '
[{"machine": "possible_victim01", "domain": "evil.com", "count": 3},  
{"machine": "possible_victim02", "domain": "bad.com", …
Run Code Online (Sandbox Code Playgroud)

json group-by counting aggregation jq

7
推荐指数
1
解决办法
4695
查看次数

标签 统计

aggregation ×1

counting ×1

group-by ×1

jq ×1

json ×1