小编Krz*_*den的帖子

我目前正在尝试将我的应用程序从MySQL数据库更改为MongoDB数据库.我的项目需要比较其中的两个,我的MySQL代码正在工作,现在它给了我这个错误.

堆栈跟踪:

遇到PHP错误严重性:通知消息:未定义属性:Users::$form_validation文件名:controllers/users.php行号:26

错误行:

$this->form_validation->set_rules('username','Username','trim|required|min_length[4]|xss_clean');   

码:

<?php
class Users extends CI_Controller{
    public function register(){ 
        $this->form_validation->set_rules('first_name','First Name','trim|required|max_length[50]|min_length[2]|xss_clean');
        $this->form_validation->set_rules('last_name','Last Name','trim|required|max_length[50]|min_length[2]|xss_clean');
        $this->form_validation->set_rules('email','Email','trim|required|max_length[100]|min_length[5]|xss_clean|valid_email');
        $this->form_validation->set_rules('username','Username','trim|required|max_length20]|min_length[6]|xss_clean');
        $this->form_validation->set_rules('password','Password','trim|required|max_length[20]|min_length[6]|xss_clean');
        $this->form_validation->set_rules('password2','Confirm Password','trim|required|max_length[50]|min_length[2]|xss_clean|matches[password]');
        if($this->form_validation->run() == FALSE){
            $data['main_content']='users/register';
            $this->load->view('layouts/main',$data);    
        }else{
            if($this->User_model->create_member()){ 
                $this->session->set_flashdata('registered','Registered successfully');
                redirect('home/index'); 
            }
        }
    }

    public function login(){
        //$this->load->model('user_model');
        $this->form_validation->set_rules('username','Username','trim|required|min_length[4]|xss_clean');      
        $this->form_validation->set_rules('password','Password','trim|required|min_length[4]|max_length[50]|xss_clean');        

        $collection = $this->database->users;

        if($this->form_validation->run() == FALSE){

            $this->session->set_flashdata('login_failed', 'Sorry, this username doesn't exist.');
            redirect('home/index');
        } else {

        $username=$_POST['login'];
        $password=$_POST['password'];

        $user_id = $collection->findOne(array('username' => $username, 'password' => md5($password)));
          // $username = $this->input->post('username');
          // $password = $this->input->post('password'); …

我目前正在研究我的JavaFX ZOO项目,我遇到了问题.我在TableView中显示所有记录,其中一列包含删除按钮.这一切都很完美,但我想点击删除按钮后出现一个警告框,只是为了安全起见.

所以我的删除按钮类看起来像这样:

    private class ButtonCell extends TableCell<Record, Boolean> {
    final Button cellButton = new Button("Delete");

    ButtonCell(){

        cellButton.setOnAction(new EventHandler<ActionEvent>(){

            @Override
            public void handle(ActionEvent t) {

                Animal currentAnimal = (Animal) ButtonCell.this.getTableView().getItems().get(ButtonCell.this.getIndex());

                data.remove(currentAnimal);
            }
        });
    }

    @Override
    protected void updateItem(Boolean t, boolean empty) {
        super.updateItem(t, empty);
        if(!empty){
            setGraphic(cellButton);
        }
    }
}

另外,我的AlertBox类看起来像这样:

public class AlertBox {

    public static void display(String title, String message){

        Stage window = new Stage();

        window.initModality(Modality.APPLICATION_MODAL);
        window.setTitle(title);
        window.setMinWidth(250);

        Label label = new Label();
        label.setText(message);
        Button …