小编Joe*_*app的帖子

无法在URL中设置包含中文字符的URL连接.它适用于拉丁字符:

String xstr = "???????????" ;
URI uri = new URI("http","ajax.googleapis.com","/ajax/services/language/detect","v=1.0&q="+xstr,null);   
URL url = uri.toURL(); 
URLConnection connection = url.openConnection();
InputStream is = connection.getInputStream() ;

getInputStream()调用导致:

java.lang.IllegalArgumentException: Invalid uri 'http://ajax.googleapis.com/ajax/services/language/detect?v=1.0&q=???????????': Invalid query