如果您转到Python 的默认安装程序下载页面并单击如下所示的漂亮黄色按钮,它将为您下载最新版本 Python 的 32 位安装程序。
要获得 64 位安装程序,您必须单击下面红色圈出的链接,然后滚动到底部以找到安装程序,例如,对于 Windows,它将是Windows x86-64 可执行安装程序
大多数 Python 开发人员仍然使用 32 位系统吗?否则,为什么 Python 不为 64 位制作默认安装程序?它确实让我困惑了 30 分钟,安装 32 位版本,卸载然后最后安装 64 位版本。
import multiprocess as mp
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mp.Pipe()和 之间的主要区别是什么mp.Queue()?它们对我来说似乎是一样的:基本上Pipe.recv()相当于Queue.get(),Pipe.send()和Queue.put()。
底部是我现在拥有的代码。它似乎工作正常。但是,我并不完全理解它。我想如果没有.join(),我会冒着代码在池完成执行之前进入下一个 for 循环的风险。我们不需要那 3 行注释掉吗?
另一方面,如果我要.close()和.join()方式一起去,有没有办法“重新打开”那个关闭的游泳池而不是Pool(6)每次?
import multiprocessing as mp
import random as rdm
from statistics import stdev, mean
import time
def mesh_subset(population, n_chosen=5):
chosen = rdm.choices(population, k=n_chosen)
return mean(chosen)
if __name__ == '__main__':
population = [x for x in range(20)]
N_iteration = 10
start_time = time.time()
pool = mp.Pool(6)
for i in range(N_iteration):
print([round(x,2) for x in population])
print(stdev(population))
# pool = mp.Pool(6)
population = pool.map(mesh_subset, [population]*len(population))
# pool.close()
# pool.join() …Run Code Online (Sandbox Code Playgroud) 执行下面的代码时出现错误。问题似乎是map不支持接受多个输入的函数,就像在 python 内置multiprocessing包中一样。但在内置包中,有一个starmap可以解决这个问题。pathos.multiprocessing有相同的吗?
import pathos.multiprocessing as mp
class Bar:
def foo(self, name):
return len(str(name))
def boo(self, x, y, z):
sum = self.foo(x)
sum += self.foo(y)
sum += self.foo(z)
return sum
if __name__ == '__main__':
b = Bar()
pool = mp.ProcessingPool()
results = pool.map(b.boo, [(12, 3, 456), (8, 9, 10), ('a', 'b', 'cde')])
print(results)
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类型错误:boo() 缺少 2 个必需的位置参数:“y”和“z”
按照建议更新 lambda 表达式(不起作用):
if __name__ == '__main__':
b = Bar()
pool = mp.ProcessingPool()
results = …Run Code Online (Sandbox Code Playgroud) 我有一个散点图,如下图所示。如何让标题区域不占用这么多空间?需要说明的是,我指的不是标题的字体大小,而是标题区域占据的空白空间。
var rstTrace = {
x: x_data,
y: y_data,
mode: 'markers',
type: 'scatter',
marker: {
size: 3,
color: chartMarkerColor
}
};
var rstLayout = {
height: 400,
title: {
text: 'My Title',
font: {
family: 'Tahoma',
size: 15
}
},
xaxis: {
showline: true,
zeroline: false,
linecolor: '#D3D3D3', // light gray
tickcolor: '#D3D3D3'
},
yaxis: {
showline: true,
zeroline: false,
linecolor: '#D3D3D3',
tickcolor: '#D3D3D3'
},
backgroundcolor: '#D3D3D3'
};
Plotly.newPlot('resultDiv', [rstTrace], rstLayout);
Run Code Online (Sandbox Code Playgroud) I'm trying to learn Spark following some hello-word level example such as below, using pyspark. I got a "Method isBarrier([]) does not exist" error, full error included below the code.
from pyspark import SparkContext
if __name__ == '__main__':
sc = SparkContext('local[6]', 'pySpark_pyCharm')
rdd = sc.parallelize([1, 2, 3, 4, 5, 6, 7, 8])
rdd.collect()
rdd.count()
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Although, when I start a pyspark session in command line directly and type in the same code, it works fine:
My setup:
是什么让之间,比方说日期的最佳方式,'2019-01-08'并且'2019-01-16',从pandas.DatetimeIndex对象dti的构造下面?理想情况下,一些简洁的语法,如dti['2019-01-08':'2019-01-16']?
import pandas as pd
dti = pd.bdate_range(start='2019-01-01', end='2019-02-15')
DatetimeIndex(['2019-01-01', '2019-01-02', '2019-01-03', '2019-01-04',
'2019-01-07', '2019-01-08', '2019-01-09', '2019-01-10',
'2019-01-11', '2019-01-14', '2019-01-15', '2019-01-16',
'2019-01-17', '2019-01-18', '2019-01-21', '2019-01-22',
'2019-01-23', '2019-01-24', '2019-01-25', '2019-01-28',
'2019-01-29', '2019-01-30', '2019-01-31', '2019-02-01',
'2019-02-04', '2019-02-05', '2019-02-06', '2019-02-07',
'2019-02-08', '2019-02-11', '2019-02-12', '2019-02-13',
'2019-02-14', '2019-02-15'],
dtype='datetime64[ns]', freq='B')
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