小编Ami*_*wal的帖子

我想在2D数组中查找对的频率。输入示例如下：

list_of_items = [[12,14,18],[12,19,54,89,105],[ 14, 19],[54, 88 ,105,178]]

预期输出如下：

(12,14):1
(12,18):1
(12,19):1
(12,54):1
(12,88):0
.
.
.
(54,105):2
.
.

我尝试了以下代码，但我认为这不是最佳解决方案：

number_set = [ 12, 14, 18,19,54,88,89 , 105, 178]

def get_frequency_of_pairs(list_of_items, number_set):
    x=1
    combination_list = []
    result = {}
    for i in number_set:
       for j in range(x,len(number_set)):
           combination_list = combination_list +[(i,number_set[j])]
       x = x+1
    for t in combination_list:
        result[t]=0
    for t in combination_list:
       for items in list_of_items:
           if( set(t).issubset(items) ):
              result[t]=result[t]+1
    return result