为了一些向后兼容性:
运行包含或使用Storyboard的应用程序的OS X的最低要求版本是多少?
在这个x86_64十六进制/反汇编代码的示例中,我看到:
48B80000000000000000 mov rax, 0x0
Signed Byte 52
Unsigned Byte 52
Signed Short 14388
Unsigned Short 14388
Signed Int 943863860
Unsigned Int 943863860
Signed Int64 3472328296363079732
Unsigned Int64 3472328296363079732
Float 4.630555e-05
Double 1.39804332763832e-76
String 48B80000000000000000
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对我来说似乎具有相同的功能:
48C7C000000000 mov rax, 0x0
48C7C000000000
Signed Byte 52
Unsigned Byte 52
Signed Short 14388
Unsigned Short 14388
Signed Int 927152180
Unsigned Int 927152180
Signed Int64 3472328377950746676
Unsigned Int64 3472328377950746676
Float 1.163599e-05
Double 1.39806836023098e-76
String 48C7C000000000
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第一个例子与第二个例子的处理方式有何不同?
我想检查NSComparisonResult是否小于或等于iOS.
1.
NSComparisonResult result = blabla...;
if (result == NSOrderedAscending || result == NSOrderedSame) {...}
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2.
NSComparisonResult result = blabla...;
if (result <= NSOrderedSame) {...}
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我可以使用选项1,但是,我可以使用选项2吗?我设计它是因为NSComparisonResult它只是NSInteger; NSOrderedSame是0,NSOrderedAscending是-1,NSOrderedDescending是1.
我一直在试图找出一种方法来递归删除xattr某些文件的所有内容,但是,以前的方法似乎都不再起作用了;也可能有一个新引入的错误?
$ xattr -rc .
option -r not recognized
$ xattr -c .
option -c not recognized
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..现在是大结局!
$ find . -exec xattr -l {} \;
com.apple.FinderInfo:
Traceback (most recent call last):
File "/usr/local/bin/xattr", line 11, in <module>
sys.exit(main())
File "/Library/Python/2.7/site-packages/xattr/tool.py", line 200, in main
print(_dump(attr_value))
File "/Library/Python/2.7/site-packages/xattr/tool.py", line 77, in _dump
printable = s.translate(_FILTER)
TypeError: character mapping must return integer, None or unicode
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哦,看它xattr在垃圾中发现了一个……知道如何、什么或谁xattr如此严重地破坏了该工具会很有趣。我只需要递归删除扩展属性,真的!