小编ten*_*ten的帖子

这个多组件不起作用;

import React from 'react';
import ReactDOM from 'react-dom';
import { Router, Route, Link, browserHistory, IndexRoute  } from 'react-router'

class App extends React.Component {
   render() {
      return (
         <div>
            <ul>
               <li><Link>Home</Link></li>
            </ul>

           {this.props.children}
         </div>
      )
   }
}

export default App;

class Home extends React.Component {
   render() {
      return (
         <div>
            <h1>Home...</h1>
         </div>
      )
   }
}

export default Home;

ReactDOM.render((
   <Router history = {browserHistory}>
      <Route path = "/" component = {App}>
         <IndexRoute component = {Home} />
         <Route path = "home" component …

我想升级ng1组件以在ng2组件中使用.

如果我只使用模板字符串ng1组件,要升级,它的工作原理.但是,如果我切换到使用templateUrl,应用程序崩溃并给我这个错误:

angular.js:13920 Error: loading directive templates asynchronously is not supported
at RemoteUrlComponent.UpgradeComponent.compileTemplate (upgrade-static.umd.js:720)
at RemoteUrlComponent.UpgradeComponent (upgrade-static.umd.js:521)
at new RemoteUrlComponent (remote-url.component.ts:11)
at new Wrapper_RemoteUrlComponent (wrapper.ngfactory.js:7)
at View_AppComponent1.createInternal (component.ngfactory.js:73)
at View_AppComponent1.AppView.create (core.umd.js:12262)
at TemplateRef_.createEmbeddedView (core.umd.js:9320)
at ViewContainerRef_.createEmbeddedView (core.umd.js:9552)
at eval (common.umd.js:1670)
at DefaultIterableDiffer.forEachOperation (core.umd.js:4653)

这是一个证明我的问题的插件:

https://plnkr.co/edit/2fXvfc?p=info

我遵循了Angular 1 - > 2升级指南,似乎这段代码应该可行.我不太确定为什么它不起作用.

我从这个github项目中知道Swift +++和<<<"运营商".

这是我很难搜索此对谷歌,因为+++和<<<也许某种特殊字符,没有出现在搜索结果的.当我写问题标题时,它甚至没有出现可能已经有 Stack Overflow的答案部分的问题.

你能简单解释一下这些奇怪的算子是什么吗？也许有些文章可以进一步阅读？

我有3个数组如下.

$array1 = Array
(
    [0] => 05/01
    [1] => 05/02
)

$array2 =Array
(
    [0] => ED
    [1] => P
)

$array3 =Array
(
    [0] => Mon
    [1] => Tue

)

我想合并这三个数组,如下所示$result_array.我编写了如下代码.但它给了一个空数组.

$result_array =Array
(
    [0] => Array
        (
            [0] => 05/01
            [1] => ED
            [2] => Mon
        )
    [1] => Array
        (
            [0] => 05/02
            [1] => P
            [2] => Tue
        )
)

码:

for($z=0; $z<count($array1); $z++){
    $all_array[$z][] = array_merge($array1[$z],$array2[$z] );
    $all_array2[$z] = array_merge($all_array[$z],$array3[$z] );
} …

我一直在努力使用RoboGuice和碎片而没有运气.我有一个扩展的片段RoboFragment,以及一个扩展的活动RoboActivity,但似乎在其中RoboActivity,该方法getFragmentManager是不兼容的RoboFragment.

它看起来像RoboFragment扩展android.support.v4.app.Fragmentment但getFragmentManager需要android.app.Fragment.

这有什么用？

我创建了一个主题，并放置了一个简单的生产者来在该主题中发布一些消息

 bin/kafka-topics.sh --create --zookeeper localhost:2181 --replication-factor 1 --partitions 1 --topic streams-file-input

bin/kafka-console-producer.sh --broker-list localhost:9092 --streams-file-input

我在 kafka 流中运行下面的简单示例，但遇到了一个我无法处理的奇怪异常

 Properties props = new Properties();
            props.put(StreamsConfig.APPLICATION_ID_CONFIG, "streams-pipe");
            props.put(StreamsConfig.BOOTSTRAP_SERVERS_CONFIG, "192.168.1.3:9092");
            props.put(StreamsConfig.KEY_SERDE_CLASS_CONFIG, Serdes.String().getClass());
            props.put(StreamsConfig.VALUE_SERDE_CLASS_CONFIG, Serdes.String().getClass());

            // setting offset reset to earliest so that we can re-run the demo code with the same pre-loaded data
            props.put(ConsumerConfig.AUTO_OFFSET_RESET_CONFIG, "earliest");

            KStreamBuilder builder = new KStreamBuilder();

            builder.stream("streams-file-input").to("streams-pipe-output");

            KafkaStreams streams = new KafkaStreams(builder, props);
            streams.start();

            // usually the stream application would be running forever,
            // in this example we just …

   import java.util.Scanner;

    public class Main {
    private static Scanner scan;
    private static int n;
    private static int b[];
    private static String a1;
    private static String a2;
    private static int t[];

    public static void main(String s[]) {
        scan = new Scanner(System.in);
        n = scan.nextInt();
        b = new int[n];
        t = new int[n];
        for (int i = 0; i < n; i++) {
            b[i] = scan.nextInt();
        }

        a1 = scan.next();
        a2 = scan.next();

        for (int i = 0; i < n; i++) …

我有一个包含 2 个文本视图的弹出窗口。

如果用户单击一个文本视图 toast 必须出现。我为此功能编码但显示Nullpointer exception在线far.setOnClickListener(new OnClickListener() {请帮助我。

我的代码：

btn_a.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            LayoutInflater lInflater = (LayoutInflater) getActivity().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            View popup_view = lInflater.inflate(R.layout.popup_a, null);
            final PopupWindow popup = new PopupWindow(popup_view,200,75,true);
            popup.setFocusable(true);
            popup.setBackgroundDrawable(new ColorDrawable());   
            popup.showAsDropDown(btn_a,  0,0);

            TextView far = (TextView) rootView.findViewById(R.id.fartext);
            far.setOnClickListener(new OnClickListener() {

                @Override
                public void onClick(View v) {
                    Toast.makeText(getActivity(), "Clicked Far", Toast.LENGTH_SHORT).show();

                }
            });
        }
    });

我有一个如下所示的数组

$array1 = Array
(
    [0] => 20225,2017-02-20
    [1] => 20225,2017-02-20
    [2] => 10027,2017-02-20
    [3] => 10027,2017-02-20
    [4] => 10021,2017-02-20
    [5] => 20205,2017-02-20
    [6] => 50003,2017-02-20
    [7] => 20225,2017-02-20
    [8] => 20205,2017-02-20
    [9] => 10021,2017-02-20
    [10] => 50003,2017-02-20
    [11] => 10027,2017-02-20
    [12] => 20225,2017-02-20
    [13] => 20225,2017-02-21
    [14] => 20225,2017-02-21
)

如果数组包含的相同结果超过 2 个，我想将其中一个值获取到另一个名为 的数组$array2。

请帮我做到这一点

我想将定义的全局变量传递给echo php中的java脚本代码.

以下是我的代码.这不起作用.请帮我解决一下这个.

echo '<script language="javascript">';
echo 'alert('.$this->msg5.')'; //not working alert here
echo '</script>';