小编Jac*_*ob 的帖子

我有这个WIQL ...

Wiql wiql = new Wiql()
  {
    Query = string.Format("SELECT [System.Id], [System.WorkItemType], [System.Title], [System.AssignedTo], [System.State]" +
                          " FROM WorkItemLinks" +
                          " WHERE Target.[System.TeamProject] = '{0}'" +
                          " AND Source.[System.Id] = {1}" +
                          " AND [System.Links.LinkType] = 'System.LinkTypes.Hierarchy-Forward'" +
                          " mode(Recursive)", project, startingChildId)
  };

我想使其与该TFS查询相匹配，其中特定工作项的所有父项都放入树中，如下所示。

我的问题是，我只从需要父级工作项的情况下获取子级工作项。我如何遍历树而不是遍历树？我已经尝试切换System.Links.LinkType到等效的父关系，但是这样做会引发不受支持的错误。

我是JavaScript的新手,不知道我哪里出错了.我想创建一个在正确的一系列keyEvents之后执行的函数.基本上,当用户按此顺序按下"j","a","c","o"和"b"键时(仅此顺序),我的网页上的元素将变为可见.目前使用CSS样式标记隐藏此元素:<div id="hideaway" style="display:none;">

<script> 

 function keyListener(event) {
	event = event || window.event; //capture the event, and ensure we have an event
    var key = event.key || event.which || event.keyCode; //find the key that was pressed
    if(key==106) { //this is for 'j'
	    document.getElementById("hideaway").style.display="block";
        event = event || window.event; //capture the event, and ensure we have an event
        var key = event.key || event.which || event.keyCode; //find the key that was pressed
		if(key==97) { //this is for 'a'
        	event = event …