我有一些代码
<input type="checkbox" id="chk" value="value" />
<label for="chk">Value </label>
<br/>
<input type="button" id="But1" value="set value" />
<br />
<input type="button" id="But2" value="read checked" />
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JavaScript的:
$(document).ready(function () {
console.log("Ready ...");
registerHandlers();
function registerHandlers() {
$('#But1').click(function () {
$('#chk').prop('checked', !$('#chk').is(':checked'));
});
$('#But2').click(function () {
var chk1 = $('#chk').is(':checked');
console.log("Value : " + chk1);
});
$('input[type="checkbox"]').change(function () {
var name = $(this).val();
var check = $(this).prop('checked');
console.log("Change: " + name + " to " + check);
});
}
});
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如何使用jQuery处理复选框的更改?我需要把处理程序更改为选中的任何复选框.
[更新]
有一个复选框和几个按钮.每个按钮都可以更改复选框.如何捕捉更改复选框的事件? …
我有这个类用于在Java中创建一个线程
package org.vdzundza.forms;
import java.awt.Graphics;
import java.awt.Graphics2D;
public class DrawThread extends Thread {
private static final int THREAD_SLEEP = 500;
public CustomShape shape;
private Graphics g;
public DrawThread(CustomShape shape, Graphics g) {
this.shape = shape;
this.g = g;
}
@Override
public void run() {
while (true) {
try {
Thread.sleep(THREAD_SLEEP);
Graphics2D g2d = (Graphics2D) g;
g2d.setColor(this.shape.getColor());
g2d.fill(this.shape.getShape());
System.out.println(String.format("execute thread: %s %s",
Thread.currentThread().getName(), this.getName()));
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
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控制台将以下文本显示为输出
execute thread: red rectangle Thread-2
execute …Run Code Online (Sandbox Code Playgroud) 我有一些表行
<tr class="b_row">
<td>
<div class="cpt">
<h2>
<a href="/ref/ref/1.html">example</a>
</h2>
</div>
</td>
</tr>
<!--more elements -->
<tr class="b_row">
<td>
<div class="cpt">
<h2>
<a href="/ref/two/23.html">example N</a>
</h2>
</div>
</td>
</tr>
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我需要在属性中获取超链接.我用这个脚本
function openAll()
{
$("tr.b_row").each(function(){
var a_href = $('div.cpt').find('h2 a').attr('href');
alert ("Href is: " + a_href);
}
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问题:变量a_href总是/ ref/ref/1.html
我有功能
public static int func(int M,int N){
if(M == 0 || N == 0) return M+N+1;
return func(M-1, func(M, N-1));
}
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如何用非递归样式重写它?也许,它实现了一些算法吗?
我使用PhpStorm编辑Apache的PHP文件和配置文件.如何评论所选块并设置符号注释?我想要,例如,
<Directory />
Options FollowSymLinks
AllowOverride None
Order deny,allow
Deny from all
</Directory>
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至
#<Directory />
# Options FollowSymLinks
# AllowOverride None
# Order deny,allow
# Deny from all
#</Directory>
Run Code Online (Sandbox Code Playgroud) 我有黑色背景色.如何更改JavaDoc窗口的背景颜色?

[UPDATE#1] 类似问题 http://www.eclipse.org/forums/index.php?t=tree&th=77817&
我想我的版本1.2到1.3的angular-animate.js存在迁移问题.这是我的动画
'use strict';
angular.module('cookbook', ['ngAnimate'])
.animation('.slide-down', function() {
var NG_HIDE_CLASS = 'ng-hide';
return {
beforeAddClass: function(element, className, done) {
alert('before add');
if(className === NG_HIDE_CLASS) {
element.slideUp(done);
}
},
removeClass: function(element, className, done) {
if(className === NG_HIDE_CLASS) {
element.hide().slideDown(done);
}
}
};
});
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同步测试
'use strict';
describe('A Brief Look At Testing Animations(changed) - ', function() {
var scope;
var element;
var $animate;
var $rootElement;
beforeEach(module('cookbook', 'ngAnimateMock'));
describe('Synchronous testing of animations', function() {
var animatedShow = false;
var animatedHide = false;
beforeEach(module(function($animateProvider) …Run Code Online (Sandbox Code Playgroud) 我有一些班级名字.如何检查一个类是否继承了另一个类而没有实例化它?
if (!class_exists($controller)) //AND I have check type
{
$objectController = new IndexController();
$objectController->index();
}
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