我正在尝试将我的数据库导入到新的数据库中但是我收到以下错误:
1064 - 您的SQL语法出错; 查看与您的MySQL服务器版本对应的手册,以便在附近使用正确的语法
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<div class="error"><h1>Error</h1>
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SQL query 在第1行
导出文件中的错误是:
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<div class="error"><h1>Error</h1>
<p><strong>SQL query:</strong>
<a href="tbl_sql.php?sql_query=SHOW+TABLE+STATUS+FROM+%60addcart138an%60+LIKE+%2 7zen_categories%27&show_query=1&db=addcart138an& amp;table=zen_categories&token=ed1d79622b85c64e6353225dce5738e8"><span class="nowrap"><img src="themes/dot.gif" title="Edit" alt="Edit" class="icon ic_b_edit" /> Edit</span></a> </p>
<p>
<span class="syntax"><span class="inner_sql"><a href="./url.php?url=http %3A%2F %2Fdev.mysql.com%2Fdoc%2Frefman%2F5.5%2Fen%2Fshow.html&token=ed1d79622b85 c64e6353225dce5738e8" target="mysql_doc"><span class="syntax_alpha syntax_alpha_reservedWord">SHOW</span></a> <span class="syntax_alpha syntax_alpha_reservedWord">TABLE</span> <span class="syntax_alpha syntax_alpha_reservedWord">STATUS</span> <span class="syntax_alpha syntax_alpha_reservedWord">FROM</span> <span class="syntax_quote syntax_quote_backtick">`addcart138an`</span> <a href="./url.php?url=http %3A%2F%2Fdev.mysql.com%2Fdoc%2Frefman%2F5.5%2Fen%2Fstring-comparison- functions.html%23operator_like&token=ed1d79622b85c64e6353225dce5738e8" target="mysql_doc"><span class="syntax_alpha syntax_alpha_reservedWord">LIKE</span></a> <span class="syntax_quote syntax_quote_single">'zen_categories'</span></span></span>
</p>
<p>
<strong>MySQL said: </strong><a href="./url.php?url=http%3A%2F %2Fdev.mysql.com%2Fdoc%2Frefman%2F5.5%2Fen%2Ferror-messages- server.html&token=ed1d79622b85c64e6353225dce5738e8" target="mysql_doc"><img src="themes/dot.gif" title="Documentation" alt="Documentation" class="icon …Run Code Online (Sandbox Code Playgroud)