here is my case:
<html>
<body>
<head>
...
<script>
$(function(){
$('.do-tip').qtip({
content: 'This is a tip of active hovered element',
show: 'mouseover',
hide: 'mouseout',
})
});
</script>
</head>
<body>
<a href="http://www.google.com" class="do-tip">google</a>
<input type="button" value="load div by ajax" />
<div> <!-- this div loaded by ajax -->
<div>
<a href="http://www.yahoo.com" class="do-tip">yahoo</a> <!-- HOW TO HERE, run the existing script only for this part, JQUERY UNCLE must have a solution-->
</body>
</html>
any ideas?
Run Code Online (Sandbox Code Playgroud) 下午好,我遇到了使用C#和Linq to Entities选择两个连接字符串的问题.目前我有两个连接字符串:
<add name="GameHutDBEntities1" connectionString="metadata=res://*/GameHutModel.csdl|res://*/GameHutModel.ssdl|res://*/GameHutModel.msl;provider=System.Data.SqlClient;provider connection string="Data Source=EMMANUEL-PC\SQLEXPRESS;Initial Catalog=GameHutDB;user id=GameHutAdmin; password=123;MultipleActiveResultSets=True"" providerName="System.Data.EntityClient" />
<add name="GameHutDBEntities2" connectionString="metadata=res://*/GameHutModel.csdl|res://*/GameHutModel.ssdl|res://*/GameHutModel.msl;provider=System.Data.SqlClient;provider connection string="Data Source=EMMANUEL-PC\SQLEXPRESS;Initial Catalog=GameHutDB;user id=test; password=1234;MultipleActiveResultSets=True"" providerName="System.Data.EntityClient" />
Run Code Online (Sandbox Code Playgroud)
我有两个角色,即Admin和Clerk.如何允许管理员使用第一个连接字符串登录,并且职员将使用第二个连接字符串登录?

JavaScript的forEach文档声明.forEach语法是:
arr.forEach(callback[, thisArg])
Run Code Online (Sandbox Code Playgroud)
有什么用thisArg?
我有这门课
public class FlightSegment{
public string ClassName { get;set;}
}
Run Code Online (Sandbox Code Playgroud)
而且我希望FlightSegments与众不同ClassName
void Main()
{
var list1 = new List<FlightSegment>() {
new FlightSegment{ ClassName = "A"},
new FlightSegment { ClassName = "B"}
};
var list2 = new List<FlightSegment>() {
new FlightSegment{ ClassName = "B"},
new FlightSegment { ClassName = "C"}
};
var listOfLists = new List<List<FlightSegment>>() { list1, list2 };
var intersection = listOfLists.Aggregate((previousList, nextList) => previousList.Intersect(nextList).ToList());
Console.WriteLine(intersection); //Gives me empty result
}
Run Code Online (Sandbox Code Playgroud)
我试过这样的事情:
var intersection = listOfLists.Aggregate((previousList, …Run Code Online (Sandbox Code Playgroud) 查询是:
var query =
from stokHareket1 in ce.StokHarekets
from stokHareket2 in ce.StokHarekets
join stok in ce.Stoks on stokHareket1.StokId equals stok.Id
where (
stokHareket1.StokId == stokHareket2.StokId
)
select new
{
result = stokHareket1.StokId
};
Run Code Online (Sandbox Code Playgroud)
在第一个项目中,EF版本是:5.0.0,第二个项目是6.1.3
它给出了第一个项目:
SELECT
[Extent1].[StokId] AS [StokId]
FROM [dbo].[StokHareket] AS [Extent1]
INNER JOIN [dbo].[StokHareket] AS [Extent2] ON [Extent1].[StokId] = [Extent2].[StokId]
WHERE [Extent1].[StokId] IS NOT NULL
Run Code Online (Sandbox Code Playgroud)
在第二个:
SELECT
[Extent1].[StokId] AS [StokId]
FROM [dbo].[StokHareket] AS [Extent1]
INNER JOIN [dbo].[StokHareket] AS [Extent2] ON ([Extent1].[StokId] = [Extent2].[StokId])
/*THIS LINE*/OR …Run Code Online (Sandbox Code Playgroud) 第一个案例:
<div>
<a href="#" onclick="doIt(this)">some job</a>
<div>
Run Code Online (Sandbox Code Playgroud)
我可以:
<script>
function doIt(caller){
alert($(caller).closest('div').html());
}
</script>
Run Code Online (Sandbox Code Playgroud)
第二种情况:
<div id="divId">
....
</div>
Run Code Online (Sandbox Code Playgroud)
我做
<script>
alert($("#divId").html());
</script>
Run Code Online (Sandbox Code Playgroud)
我怎么能用onclick(这个)将第一个案例mecanism应用到第二个案例?
关于问题的更多细节:
第一种情况,因为我使用锚onclick,我可以得到动作源然后它的父.
第二种情况,另一方面,有div块和脚本块之后.它们在页面中呈现,因此没有单击事件.我需要个东西:
$(本).closest( 'DIV').HTML()但它不起作用
Id元素在整个文档中是唯一的,没关系.这个怎么样
$("#Genders", $("#tableFor_SEARCH")).buttonset();
Run Code Online (Sandbox Code Playgroud)
和
$("#Genders", $("#tableFor_CREATE")).buttonset();
Run Code Online (Sandbox Code Playgroud)
firefox看起来还不错,这个用法可以接受所有浏览器和任何缺点吗?
注意:我尝试这种用法,因为jquery使用id选择器和radio&checkbox助手(特别是标签标签)
c# ×3
jquery ×3
linq ×2
aggregate ×1
ajax ×1
asp.net ×1
foreach ×1
html ×1
intersection ×1
javascript ×1