小编fre*_*all的帖子

我已将Kibana连接到我的ES实例.

cat/indices返回:

yellow open .kibana 1 1      1 0 3.1kb 3.1kb 
yellow open tests   5 1 413042 0 3.4gb 3.4gb 

但是我在kibana配置屏幕上得到以下内容.我错过了什么？

更新:

我的示例文档如下所示

    "_index": "tests",
    "_type": "test7",
    "_id": "AVGlIKIM1CQ8BZRgLZVg",
    "_score": 1.7840601,
    "_source": {
       "severity": "ERROR",
       "code": "CODE,
       "message": "MESSAGE",
       "environment": "TEST",
       "error_uuid": "cbe99080-0bf3-495c-a417-77384ba0fd39",
       "correlation_id": "cf5a1fd5-4fd2-40bb-9cdf-405b91dcbd6f",
       "timestamp": "2015-11-20 15:24:39.831"

过了一段时间,我决定回去学习一些函数式编程.我这次决定选择Haskell,因为它的功能和语法.

目前我正在做一些练习而且我被困住了.我想编写一个函数,从列表中选择第二个最后一个元素,即给定[1,2,3,4]它将为3.

这是我的功能.

lastButOne xs 
    | null xs = xs 
    | length xs == 1 = xs 
    | length xs == 2 = lastButOne head xs
    | otherwise = lastButOne tail xs

不幸的是,它产生了一些错

Couldn't match expected type `[a]' with actual type `[a1] -> [a1]'
Relevant bindings include
  xs :: [a] (bound at lastButOne.hs:1:12)
  lastButOne :: [a] -> [a] (bound at lastButOne.hs:1:1)
Probable cause: `tail' is applied to too few arguments
In the first argument of `lastButOne', namely `tail'
In the …

我有一个具有以下结构的 JSON 数据

[{
"a1":"b1",
"a2":"b2",
"details1":[{"a1":"b1"}],
"details2":[{"a2":"b2"}],
},
{
"a1":"b1",
"a2":"b2",
"details1":[{"a1":"b1"}],
"details2":[{"a2":"b2"}],
},
{
"a1":"b1",
"a2":"b2",
"details1":[{"a1":"b1"}],
"details2":[{"a2":"b2"}],
}]

我为 details1 和 details2 数组创建了单独的报告。此外，我为主表的一个元素创建了一个报告，将 details1 和 details2 报告作为子报告。

问题是主报告只打印第一个元素的 a1 和 a2，然后打印所有元素的所有 details1 和 details2 表中的所有元素。

我的目标是创建一个报告，从主表的第一个元素打印 a1、a2、details1、details2，然后是第二个元素，依此类推。我怎样才能做到这一点？

换句话说，如何在 JSON 数组上迭代相同的报告模板？