#include <stdlib.h>
#include <stdio.h>
struct node;
typedef struct node* PtrToNode;
struct node {
long long n;
PtrToNode next;
};
PtrToNode factorial(int n, PtrToNode init);
void multiply(long long n, PtrToNode init, long long carry);
int main() {
int n;
while (1) {
scanf("%d", &n);
if (n > 0) {
break;
} else if (n == 0){
printf("1\n");
return 0;
} else {
printf("Retry.\n");
}
}
PtrToNode init = malloc(sizeof(struct node));
init->n = 1;
init->next = NULL;
PtrToNode head = factorial(n, init); …现在,我想使用cuda运行pytorch,然后我使用model.cuda(),并且torch.cuda.LongTensor()用于所有张量..cuda.如果我使用过,我是否必须明确使用张量model.cuda()？有没有办法让所有计算在GPU中运行为默认值？
我正在使用ipython 4.0.1和python 3.5.1,当我调用np.c_()时,它显示错误
CClass object is not callable.
这是我的代码:
import numpy as np
rows = []
with open('ntumlone.dat') as f:
rows = [list(map(float, L.split())) for L in f]
arr = np.array(rows)
date = np.c_(np.ones(len(arr)), arr)
我怎么了？
在Arch中,当我使用Vim Vundle的PluginInstall/PluginUpdate时,它会显示许多错误消息
Processing 'tpope/vim-fugitive'
Error detected while processing function vundle#installer#new..<SNR>146_process..vundle#installer#run..vundle#installer#ins
tall..<SNR>146_sync..<SNR>146_make_sync_command..<SNR>146_get_current_origin_url..<SNR>146_system:
line 1:
E484: Can't open file /tmp/v8J8IUB/7
Error detected while processing function vundle#installer#new..<SNR>146_process..vundle#installer#run..vundle#installer#ins
tall..<SNR>146_sync:
line 6:
E714: List required
Error detected while processing function vundle#installer#new..<SNR>146_process:
line 13:
E121: Undefined variable: s:last_status
E15: Invalid expression: 'error' == s:last_status
line 17:
E121: Undefined variable: s:last_status
-- More --
我必须Enter重复键入以便process下一个插件,并在处理每个插件时,它将显示相同的错误消息:
Processing 'sjl/gundo.vim'
Error detected while processing function vundle#installer#new..<SNR>146_process..vundle#installer#run..vundle#installer#ins
tall..<SNR>146_sync..<SNR>146_make_sync_command..<SNR>146_get_current_origin_url..<SNR>146_system:
line 1:
E484: Can't open file /tmp/v8J8IUB/12
Error detected …如何使用球拍格式化输出？我想输出一个固定宽度的数字,如果小的话,用0填充它？热得到它？我搜索了球拍文件,但只能找到fprintf,似乎无法做到.
我想将矩阵的每一列添加到 numpy 数组，但numpy.broadcast只允许将矩阵的每一行添加到数组。我怎样才能做到这一点？
我的想法是首先转置矩阵，然后将其添加到数组中，然后转置回来，但这使用了两次转置。有没有一个函数可以直接实现呢？
我已经安装了oh-my-fish和bobthefish它们,我想使用bobthefish主题,我遵循他的建议并投入Theme bobthefish我的~/.config/fish/config.fish运行omf install,但它报告了一个错误:
fish: Unknown command 'Theme bobthefish'
~/.config/fish/config.fish (line 19): Theme bobthefish
^
from sourcing file ~/.config/fish/config.fish
called during startup
这是我的config.fish:
# Path to your oh-my-fish.
set -g OMF_PATH $HOME/.local/share/omf
# Path to your oh-my-fish configuration.
set -g OMF_CONFIG $HOME/.config/omf
fish_vi_mode
set --export EDITOR "vim"
### Configuration required to load oh-my-fish ###
# Note: Only add configurations that are required to be set before oh-my-fish is loaded.
# For …